Mensuration Test

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Mensuration Test - 13

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Weekly Quiz Competition

Question 1
1 / -0

A figure is formed by putting two squares one on the other as shown in the figure. If the length of each side of the two squares is $$8cm$$, then the perimeter of the figure formed is ________ .

A
$$56cm$$

B
$$64cm$$

C
$$32cm$$

D
$$48cm$$

Solution

$$\Rightarrow$$ $$ABCF$$ and $$FCDE$$ are two squares.
Length of each side of square is $$8\,cm$$.
$$\Rightarrow$$ Perimeter of ABCD $$=$$ $$AB+BC+CD+DE+EF+FA$$
$$\Rightarrow$$ Perimeter of ABCD $$=$$ $$8 + 8 + 8 + 8 + 8 + 8$$
$$\therefore$$ Perimeter of ABCD $$=$$ $$48 cm.$$
Question 2
1 / -0

The length and breadth of a rectangular field are $$260m$$ and $$130m$$ respectively, then its area is ______ .

A
$$338$$

B
$$3380$$

C
$$3800$$

D
$$33800$$

Solution

$$\Rightarrow$$ Here, length and breadth of rectangular field is $$260\,m$$ and $$130\,m$$.
$$\Rightarrow$$ Area of rectangular field = $$length \times breadth$$
$$\therefore$$ Area of rectangle = $$260\,m\times 130\,m=33800\,m^2$$
Question 3
1 / -0

What is the perimeter of a rectangle with length $$=4\ cm$$ and breadth $$=2\ cm$$?

A
$$6\ cm$$

B
$$12\ cm$$

C
$$32\ cm^{2}$$

D
$$8\ cm^{2}$$

Solution

The perimeter of a rectangle is $$2(l+b)$$

The measurements of given rectangle are $$l=4cm,\ b=2cm$$

Perimeter of Given rectangle$$=2(4+2)cm$$ $$=12cm$$
Question 4
1 / -0

The perimeter of the rectangle whose length is $$24\ cm$$ and the diagonal is $$30\ cm$$ is:

A
$$84\ cm$$

B
$$42\ cm$$

C
$$54\ cm$$

D
$$108\ cm$$

Solution

Length of rectangle $$ (l) $$ is 24 cm.

Length of diagonal $$ (d) $$ is 30 cm.

Let the length of breadth be $$ b $$.

Write the formula to calculate the diagonal of rectangle.

$$ d=\sqrt{b^{2}+h^{2}} $$ (1)

Substitute the values in equation (1).

$$ 30 = \sqrt{b^{2}+\left ( 24 \right )^{2}} $$

Solve for $$ b $$.

$$ b^{2}=900-576 $$

$$ b^{2}=324 $$

$$ b=\pm 18 $$

Since the breath cannot be negative. So, neglect the negative value of breadth. Hence, the breadth of the rectangle is $$ 18 $$ cm.

Write the formula to calculate perimeter of rectangle.

$$ P=2\left ( l+b \right ) $$ (2)

Substitute the values in equation (2).

$$ P=2\left ( 24+18 \right ) $$

$$ =2\left ( 42 \right ) $$

$$ =84 $$

Thus, the perimeter of rectangle is $$ 84 $$ cm.
Question 5
1 / -0

Find the perimeter of a square of length $$25 \,cm$$ .

A
$$625$$cm

B
$$100$$cm

C
$$125$$cm

D
$$25$$cm

Solution

We have the perimeter of a square$$=4\times side$$

therefore the perimeter of a square of length $$25$$ cm is $$=4\times 25=100$$ cm.
Question 6
1 / -0

If the perimeter of a rectangular field is 200 m add its breadth is 40 m then its area is (in $$m^2$$):

A
1200

B
2400

C
4800

D
6000

Solution

Perimeter of the rectangular field $$=2(l+b)$$
where l and b are the length and breadth of the rectangular field
$$\Rightarrow 200=2(l+40)$$
$$\Rightarrow l+40=100$$
$$\Rightarrow l=60\ m$$
Area of the rectangular field $$=lb$$
$$=60\times40$$
$$=2400\ m^2$$
Question 7
1 / -0

The length of a garden is $$200$$ m and its area is $$3$$ hectares $$20$$ ares. What is the breadth of the garden?

A
$$320$$ m

B
$$240$$ m

C
$$180$$ m

D
$$160$$ m

Solution
Question 8
1 / -0

The length of a rectangle is $$9$$ cm and its breadth is $$y$$ cm. Its perimeter (in cm) is

A
$$(y+9)+2$$

B
$$2\times (y+9)$$

C
$$2y+9$$

D
$$y+18$$

Solution
Question 9
1 / -0

Side of a square garden in 30 m. If the scale used to draw its picture is 1cm: 5m, the perimeter of the square in the picture is

A
20 cm

B
24 cm

C
28 cm

D
30 cm

Solution

The correct answer is option $$(b)$$.
Given, the side of a square garden = $$30\ m$$
We know that, the perimeter of a square $$= 4\times \text{ side}$$
So, the perimeter of a square garden $$= 4 \times 30 = 120\ m$$
The scale used to draw its picture is $$1\ cm: 5\ m$$
So, the perimeter of a square in the picture $$= 120 \div 5=24\ cm$$
Question 10
1 / -0

$$12 \text{ m}^2$$ is the area of.

A
A square with side $$12 \text{ m}$$

B
$$12$$ squares with side $$1 \text{ m}$$ each

C
$$3$$ squares with side $$4 \text{ m}$$ each

D
$$4$$ squares with side $$3 \text{ m}$$ each

Solution

According to the option $$B,$$
$$12$$ squares with side $$1\text{ m}$$ each,
Area of $$1$$ square $$= side \times side $$
Area of $$12$$ squares $$ \Rightarrow 12 \times 1 \times 1 =12\text{ m}^2$$.

Hence, option $$B$$ is correct.

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Re-Attempt Weekly Quiz Competition

Mensuration Test - 13

Result

Mensuration Test - 13

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SHARING IS CARING

Question 1

$$56cm$$

$$64cm$$

$$32cm$$

$$48cm$$

Solution

Question 2

$$338$$

$$3380$$

$$3800$$

$$33800$$

Solution

Question 3

$$6\ cm$$

$$12\ cm$$

$$32\ cm^{2}$$

$$8\ cm^{2}$$

Solution

Question 4

$$84\ cm$$

$$42\ cm$$

$$54\ cm$$

$$108\ cm$$

Solution

Question 5

$$625$$cm

$$100$$cm

$$125$$cm

$$25$$cm

Solution

Question 6

1200

2400

4800

6000

Solution

Question 7

$$320$$ m

$$240$$ m

$$180$$ m

$$160$$ m

Solution

Question 8

$$(y+9)+2$$

$$2\times (y+9)$$

$$2y+9$$

$$y+18$$

Solution

Question 9

20 cm

24 cm

28 cm

30 cm

Solution

Question 10

A square with side $$12 \text{ m}$$

$$12$$ squares with side $$1 \text{ m}$$ each

$$3$$ squares with side $$4 \text{ m}$$ each

$$4$$ squares with side $$3 \text{ m}$$ each

Solution

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