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Playing with Numbers Test - 21

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Playing with Numbers Test - 21
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Weekly Quiz Competition
  • Question 1
    1 / -0
    Which of the following numbers have most number of divisors?
    Solution
    $$176 = 2\times 2\times 2\times 2\times 11$$
    $$182 = 2\times 7\times 13$$
    $$99 = 3\times 11\times 3$$
    $$101$$ is a prime so has only 1 and itself as factors.
    Hence, clearly, $$176$$ has the greatest number of divisors.
  • Question 2
    1 / -0
    What is the H.C.F. of $$4 \times 27 \times 3125, 8 \times 9 \times 25\times 7, 16 \times 81 \times 5 \times 11\times 49?$$
    Solution
    We have
    $$\displaystyle 4\times27\times3125=2\times2\times3\times3\times3\times5\times5\times5\times5\times5$$
    $$\displaystyle 8\times 9\times 25\times 7=2\times2\times2\times3\times3\times 5\times5\times 7$$
    $$\displaystyle 16\times 81\times 5\times 11\times 49=2\times2\times2\times2\times 3\times3\times3\times3\times 5\times 11\times 7\times7$$
    Therefore, H.C.F. $$=$$ $$\displaystyle 2\times2\times 3\times3\times 5=4\times 9\times 5=180$$
  • Question 3
    1 / -0
    Among the following numbers, number which is divisible by $$2$$ is
    Solution
    A number is divisible by $$2$$ if its last digit is an even number (i.e.$$ 0,2,4,6\  or\  8$$).

    $$\therefore 72,028$$ is divisible by $$2$$ because its last digit is an even i.e $$8$$
    Rest all numbers  have last digit odd. 
    So, option C is correct.
  • Question 4
    1 / -0
    (i) Every prime number is odd.
    (ii) The product of any two prime numbers is odd.
    Which of the above statements(s) is/are correct? 
  • Question 5
    1 / -0
    Consider the following statements:
    A. The sum of two prime numbers is a prime number. 
    B. The product of two prime numbers is a prime number. 
    Which of these statements is/are correct ?
    Solution
    Neither the sum nor the product of two prime numbers is a prime number
    Eg.$$3+5=8 $$ not a prime number.
    $$3\times 5=15 $$ not a prime number.
  • Question 6
    1 / -0
    HCF of the numbers $$24,36$$ and $$92$$ is 
    Solution

    Factors of $$ 24 =1,2,3,4,6,8,12,24 $$
    Factors of $$36= 1,2,3,4,6,9,12,18,36$$

    Factors of $$ 92=1,2,4,23,46,92 $$

    Common factors are $$ =1,2,4 $$
    $$\therefore $$ HCF $$=4.$$
  • Question 7
    1 / -0
    Choose the co-prime numbers from the following pairs:
    Solution
    A set of numbers which do not have any other common factor other than $$1$$ are called co-prime.
    HCF of $$ 36 = 2 \times 2 \times 3 \times 3$$ and $$ 25 = 5 \times 5 $$ is 1 so they are co prime numbers.
  • Question 8
    1 / -0
    Which of the following statement is true?
    Solution
    $${\because}$$ All the given statements are false.
  • Question 9
    1 / -0
    HCF of the numbers  120, 144 and 216 is __.
    Solution
    Given numbers are $$120,\ 144\ and \ 216$$.
    To find out: HCF of the given numbers.

    On factorising the given numbers, we get:
    $$120=2 \times 2 \times 2 \times 3 \times 5$$
    $$144=2 \times 2 \times 2 \times 2 \times 3 \times 3 $$
    $$216=2 \times 2 \times 2 \times 3 \times 3 \times 3 $$

    The common factors amongst the three numbers are:
    $$2 \times 2 \times 2 \times 3 = 24.$$

    Hence, the HCF of $$120,\ 144\ and \ 216$$ is $$24$$.
  • Question 10
    1 / -0
    Example for co-prime numbers from the below options is ?
    Solution
    The two numbers which have only 1 as their common factor are called co-primes.

    Out of the given pair of numbers,
    Factors of $$ 25 $$  are $$ 1, 5, 25 $$
    Factors of $$ 14 $$ are $$ 1, 2, 7, 14 $$
    Their common factor is $$ 1 $$.
    Hence $$ 25, 14 $$ are co-prime numbers.


    While other options has common factors other than $$1$$.
    For option $$B$$ the common factor is $$2$$.
    For option $$C$$ the common factor is $$3$$.
    For option $$D$$ the common factor is $$11$$.
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