Fractions Test

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Fractions Test - 14

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Weekly Quiz Competition

Question 1
1 / -0

The sum of $$\displaystyle \frac { 5 }{ 17 } , \frac {4} {17} and \frac {6} {17} is $$

A
$$\displaystyle \frac { 15 }{ 51} $$

B
$$\displaystyle \frac { 17 }{ 17 }$$

C
$$\displaystyle \frac { 15 }{ 17 } $$

D
$$\displaystyle \frac { 14 }{ 17 }$$

Solution

Sum $$=\displaystyle \dfrac { 5 }{ 17 } + \dfrac {4} {17} + \dfrac {6} {17}$$

$$=\dfrac{5+4+6}{17}$$

$$= \dfrac {15} {17} $$
Question 2
1 / -0

Compare $$\displaystyle \frac { 8 }{ 16 } \Box \frac { 8 }{ 4 } $$

A
=

B
<

C
>

D
None of these

Solution

$$ \dfrac{8}{16}=\dfrac{1}{2}\ and\ \dfrac{8}{4}=2$$

obviously $$\dfrac{1}{2} < 2$$
Question 3
1 / -0

Example for an improper fraction is -

A
$$\displaystyle \frac { 35 }{ 36 } $$

B
$$\displaystyle \frac { 11 }{ 4 } $$

C
$$\displaystyle \frac { 12 }{ 14 } $$

D
$$\displaystyle \frac { 17 }{ 20 } $$

Solution

In a fraction, if the denominator is less than the numerator, then it is called as an improper fraction.

Among these, in $$\dfrac {11}{4}$$, the denominator is greater than the numerator.

Hence it is an improper fraction.
Question 4
1 / -0

Subtract $$\displaystyle \frac { 3 }{ 17 } from \frac {8} {17} $$

A
$$\displaystyle \frac { 5 }{ 34 } $$

B
$$\displaystyle \frac { 5 }{ 17 } $$

C
$$\displaystyle \frac { 5 }{ 0 } $$

D
$$\displaystyle \frac { 11 }{ 17 } $$

Solution

$$\displaystyle \frac { 8 }{ 17 } - \frac {3} {17} = \frac {5} {17}$$
Question 5
1 / -0

What fraction on the number line below is in the wrong place?

A
$$\dfrac {1}{4}$$

B
$$\dfrac {1}{8}$$

C
$$\dfrac {1}{2}$$

D
$$\dfrac {3}{4}$$

Solution

$$\dfrac 1 8$$ is a smaller value than $$\dfrac1 4$$.

So $$\dfrac 18$$ should be mentioned on the left of $$\dfrac 14.$$

So, we can conclude that $$\dfrac 1 8$$ is in the wrong place.

So option B is the correct answer.
Question 6
1 / -0

Difference of $$\dfrac {19}{25}$$ and $$\dfrac {27}{25}$$ is

A
$$\dfrac {9}{25}$$

B
$$\dfrac {3}{25}$$

C
$$\dfrac {8}{25}$$

D
$$\dfrac {6}{25}$$

Solution

Due to the common denominator, we'll easily find the difference,
$$\dfrac{(27-19)}{25}$$

$$=\dfrac 8{25}$$

So option C is the correct answer.
Question 7
1 / -0

Improper fraction of $$12\dfrac {1}{6}$$ is

A
$$\dfrac {72}{6}$$

B
$$\dfrac {73}{6}$$

C
$$\dfrac {108}{6}$$

D
$$\dfrac {85}{6}$$

Solution

$$\dfrac {WN\times D+N}{D}$$
$$\dfrac {12\times 6+1}{6}=\dfrac {72+1}{6}=\dfrac {73}{6}$$
Question 8
1 / -0

Sum of $$\dfrac {7}{12}, \dfrac {12}{12}, \dfrac {8}{12}$$ is

A
$$\dfrac {26}{12}$$

B
$$\dfrac {19}{12}$$

C
$$\dfrac {27}{12}$$

D
$$\dfrac {23}{12}$$

Solution

Therefore, $$\dfrac{7}{12}+\dfrac{12}{12}+\dfrac{8}{12}=\dfrac{27}{12}$$

As $$7+12+8=27$$

So option C is the correct answer.
Question 9
1 / -0

Mixed fraction for $$\dfrac {39}{12}$$ is

A
$$3\dfrac {1}{12}$$

B
$$3\dfrac {2}{12}$$

C
$$3\dfrac {3}{12}$$

D
$$2\dfrac {14}{12}$$

Solution

To convert an improper fraction to a mixed fraction, we divide the numerator by the denominator, then write down the whole number answer. Finally, we write down any remainder above the denominator.

So, in this case when $$39$$ is divided by $$12$$ then it leaves the remainder equal to $$3$$ and the quotient is $$3$$ as well.
$$\dfrac{{39}}{{12}} = 3\dfrac{3}{{12}}$$

So, option $$C$$ is correct.
Question 10
1 / -0

The sum of $$\displaystyle \frac{4}{13},\frac{3}{13}$$ and $$\displaystyle \frac{5}{13}$$ is __________

A
$$\displaystyle \frac{12}{39}$$

B
$$\displaystyle \frac{13}{13}$$

C
$$\displaystyle \frac{12}{13}$$

D
$$\displaystyle \frac{11}{13}$$

Solution

The sum of $$\displaystyle \frac{4}{13},\frac{3}{13}$$ and $$\displaystyle \frac{5}{13}$$ is

$$\displaystyle \frac{14}{13}+\frac{3}{13}+\frac{5}{13}=\frac{4+3+5}{13}=\frac{12}{13}$$

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Re-Attempt Weekly Quiz Competition

Fractions Test - 14

Result

Fractions Test - 14

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SHARING IS CARING

Question 1

$$\displaystyle \frac { 15 }{ 51} $$

$$\displaystyle \frac { 17 }{ 17 }$$

$$\displaystyle \frac { 15 }{ 17 } $$

$$\displaystyle \frac { 14 }{ 17 }$$

Solution

Question 2

=

<

>

None of these

Solution

Question 3

$$\displaystyle \frac { 35 }{ 36 } $$

$$\displaystyle \frac { 11 }{ 4 } $$

$$\displaystyle \frac { 12 }{ 14 } $$

$$\displaystyle \frac { 17 }{ 20 } $$

Solution

Question 4

$$\displaystyle \frac { 5 }{ 34 } $$

$$\displaystyle \frac { 5 }{ 17 } $$

$$\displaystyle \frac { 5 }{ 0 } $$

$$\displaystyle \frac { 11 }{ 17 } $$

Solution

Question 5

$$\dfrac {1}{4}$$

$$\dfrac {1}{8}$$

$$\dfrac {1}{2}$$

$$\dfrac {3}{4}$$

Solution

Question 6

$$\dfrac {9}{25}$$

$$\dfrac {3}{25}$$

$$\dfrac {8}{25}$$

$$\dfrac {6}{25}$$

Solution

Question 7

$$\dfrac {72}{6}$$

$$\dfrac {73}{6}$$

$$\dfrac {108}{6}$$

$$\dfrac {85}{6}$$

Solution

Question 8

$$\dfrac {26}{12}$$

$$\dfrac {19}{12}$$

$$\dfrac {27}{12}$$

$$\dfrac {23}{12}$$

Solution

Question 9

$$3\dfrac {1}{12}$$

$$3\dfrac {2}{12}$$

$$3\dfrac {3}{12}$$

$$2\dfrac {14}{12}$$

Solution

Question 10

$$\displaystyle \frac{12}{39}$$

$$\displaystyle \frac{13}{13}$$

$$\displaystyle \frac{12}{13}$$

$$\displaystyle \frac{11}{13}$$

Solution

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