Fractions Test

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Fractions Test - 23

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Question 1
1 / -0

Mixed fraction for $$\displaystyle \frac{39}{12}$$ is

A
$$\displaystyle 3\tfrac{1}{12}$$

B
$$\displaystyle 3\tfrac{2}{12}$$

C
$$\displaystyle 3\tfrac{3}{12}$$

D
$$\displaystyle 2\tfrac{14}{12}$$

Solution

To convert an improper fraction to a mixed fraction, we divide the numerator by the denominator, then write down the whole number answer.

Finally we write down any remainder above the denominator.

$$39÷12=3$$ leaving remainder $$3$$

Therefore, the answer will be, $$3$$ whole $$\dfrac {3}{12}$$

Hence, the mixed fraction of $$\dfrac {39}{12}$$ is $$3\dfrac {3}{12}$$.
Question 2
1 / -0

In improper fraction the numerator is always _______ the denominator

A
less than

B
greater than

C
equal to

D
none

Solution

In an improper fraction, the numerator is always $$greater\ than$$ the denominator.
Hence, the answer is 'greater than'.
Question 3
1 / -0

Difference of $$\displaystyle \frac{19}{25}$$ and $$\displaystyle \frac{27}{25}$$ is

A
$$\displaystyle \frac{9}{25}$$

B
$$\displaystyle \frac{3}{25}$$

C
$$\displaystyle \frac{8}{25}$$

D
$$\displaystyle \frac{6}{25}$$

Solution

Difference of the fractions $$\dfrac{19}{25}$$ and $$\dfrac{27}{25}$$ is
$$\dfrac{27-19}{25} =\dfrac{8}{25} $$
Hence, the answer is $$\dfrac{8}{25}$$.
Question 4
1 / -0

Subtract $$\displaystyle\frac{11}{35}$$ from $$\displaystyle\frac{12}{15}$$

A
$$\displaystyle\frac{84}{35}$$

B
$$\displaystyle\frac{33}{35}$$

C
$$\displaystyle\frac{11}{15}$$

D
$$\displaystyle\frac{17}{35}$$

Solution

The subtraction of the fraction $$\dfrac{11}{35}$$ from $$\dfrac{12}{15} $$ can be written as
$$\dfrac{12}{15}-\dfrac{11}{35}$$
LCM of $$35$$ and $$15$$ is $$105$$
$$\therefore \dfrac{12}{15}-\dfrac{11}{35}$$ $$=\dfrac{12\times7-11\times3}{105} = \dfrac{51}{105}$$
After simplifying it can be written as $$\dfrac{17}{35} $$.
Hence, the answer is $$\dfrac{17}{35} $$.
Question 5
1 / -0

Sum of $$\displaystyle \frac{7}{12},\frac{12}{12},\frac{8}{12}$$ is

A
$$\displaystyle \frac{26}{12}$$

B
$$\displaystyle \frac{19}{12}$$

C
$$\displaystyle \frac{27}{12}$$

D
$$\displaystyle \frac{23}{12}$$

Solution

In all the three fractions $$\displaystyle \frac{7}{12},\frac{12}{12},\frac{8}{12}$$ , denominators are same
So, the sum of the fraction is
$$\dfrac{7+12+8}{12}= \dfrac{27}{12}$$.
Hence, the answer is $$\dfrac{27}{12}$$.
Question 6
1 / -0

Peggy needs to ship two packages. The first package weighs pounds $$16 \dfrac14$$, and the second package weighs $$23\dfrac38$$ pounds. What is the total weight of the packages that Peggy needs to ship?

A
$$38 \dfrac89$$ pounds

B
$$39 \dfrac58$$ pounds

C
40 pounds

D
$$40 \dfrac58$$ pounds

Solution
Question 7
1 / -0

Convert $$\dfrac{7}{4}$$ into mixed fraction.

A
$$1\dfrac{3}{4}$$

B
$$2\dfrac{3}{4}$$

C
$$6\dfrac{3}{4}$$

D
None of the above

Solution

$$\dfrac{7}{4}=1\dfrac{3}{4}$$

So, option A is correct.
Question 8
1 / -0

What should be subtracted from $$\dfrac {-7}{8}$$ so as to get $$\dfrac {5}{12}$$?

A
$$\dfrac {31}{24}$$

B
$$\dfrac {8}{5}$$

C
$$\dfrac {-31}{24}$$

D
$$\dfrac {-6}{8}$$

Solution

Let the number be $$x$$ to be subtracted from $$\dfrac {-7}{8}$$ to get $$\dfrac {5}{12}$$. Then it can be solved as follows:

$$\dfrac { -7 }{ 8 } -x=\dfrac { 5 }{ 12 }$$

$$\Rightarrow -\dfrac { 7 }{ 8 } -x=\dfrac { 5 }{ 12 }$$

$$\Rightarrow -\dfrac { 7 }{ 8 } -\dfrac { 5 }{ 12 }=x$$

$$\Rightarrow x=-\dfrac { 7 }{ 8 } -\dfrac { 5 }{ 12 }$$

$$\Rightarrow x=-\dfrac { 7\times 3 }{ 8\times 3 } -\dfrac { 5\times 2 }{ 12\times 2 }$$

$$\Rightarrow x=-\dfrac { 21 }{ 24 } -\dfrac { 10 }{ 24 }$$

$$\Rightarrow x=\dfrac { -21-10 }{ 24 }$$

$$\Rightarrow x=-\dfrac { 31 }{ 24 }$$

Hence, $$x=-\dfrac { 31 }{ 24 }$$
Question 9
1 / -0

Convert $$\dfrac{11}{4}$$ into a mixed fraction.

A
$$\displaystyle 2\frac{3}{4}$$

B
$$\displaystyle 3\frac{3}{4}$$

C
$$\displaystyle 1\frac{3}{4}$$

D
none of the above

Solution

Divide $$11$$ by $$4$$. The quotient is $$2$$ and remainder $$3$$.

$$\therefore \displaystyle \frac{11}{4}= 2\frac{3}{4}$$

So. option A is correct.
Question 10
1 / -0

Which of the following statement is true?

A
Fractions with same numerator are called like fractions

B
Fractions with same denominator are called unlike fractions

C
Difference of two like fractions $$\displaystyle =\frac{difference\,of\,numerator}{common\,denominator}$$

D
A fraction with numerator greater than or equal to the denominator is called proper fraction

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Fractions Test - 23

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Fractions Test - 23

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Question 1

$$\displaystyle 3\tfrac{1}{12}$$

$$\displaystyle 3\tfrac{2}{12}$$

$$\displaystyle 3\tfrac{3}{12}$$

$$\displaystyle 2\tfrac{14}{12}$$

Solution

Question 2

less than

greater than

equal to

none

Solution

Question 3

$$\displaystyle \frac{9}{25}$$

$$\displaystyle \frac{3}{25}$$

$$\displaystyle \frac{8}{25}$$

$$\displaystyle \frac{6}{25}$$

Solution

Question 4

$$\displaystyle\frac{84}{35}$$

$$\displaystyle\frac{33}{35}$$

$$\displaystyle\frac{11}{15}$$

$$\displaystyle\frac{17}{35}$$

Solution

Question 5

$$\displaystyle \frac{26}{12}$$

$$\displaystyle \frac{19}{12}$$

$$\displaystyle \frac{27}{12}$$

$$\displaystyle \frac{23}{12}$$

Solution

Question 6

$$38 \dfrac89$$ pounds

$$39 \dfrac58$$ pounds

40 pounds

$$40 \dfrac58$$ pounds

Solution

Question 7

$$1\dfrac{3}{4}$$

$$2\dfrac{3}{4}$$

$$6\dfrac{3}{4}$$

None of the above

Solution

Question 8

$$\dfrac {31}{24}$$

$$\dfrac {8}{5}$$

$$\dfrac {-31}{24}$$

$$\dfrac {-6}{8}$$

Solution

Question 9

$$\displaystyle 2\frac{3}{4}$$

$$\displaystyle 3\frac{3}{4}$$

$$\displaystyle 1\frac{3}{4}$$

none of the above

Solution

Question 10

Fractions with same numerator are called like fractions

Fractions with same denominator are called unlike fractions

Difference of two like fractions $$\displaystyle =\frac{difference\,of\,numerator}{common\,denominator}$$

A fraction with numerator greater than or equal to the denominator is called proper fraction

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