Quantitative Aptitude (QA) Test - 36

Distance covered by Satendra in 3 hours = 2 * 45 = 90 km

Remaining distance = 882 - 90 = 792 km

Meeting time = 792/(45 + 54) = 8 hours

So, after meeting, distance covered by Satendra = 8 * 54 = 432 km

At 5:00, hour hand must be at 5 * 30 = 150 degree from 12 (clockwise).

Minute hand of the clock moves with 6 degree per minute speed and hour hand moves at 1/2 degree per minute.

Angle between two hands at 5 : 10 am = 5 * 30 + 10 * 1/2 - 10 * 6 = 95°

Now, angle decreased by 40% = 95 * 60/100 = 57°

Let now minutes hand at x min.

So, 5 * 30 + x * 1/2 - x * 6 = 57°

=> 11x/2 = 150 - 57 = 93

=> x = 186/11 min

So, at 5h 186/11 min the required angle will be formed.

Let the total cost price of all articles be Rs. 100k and total selling price of all articles be Rs. 120k.

Selling price of pillows = 35% of Total selling price = 0.35 (120k) = Rs. 42k

Selling price of bedsheets = 150% of selling price of pillows = 3/2 * 42k = Rs. 63k

So, selling price of curtains = 120k - 42k - 63k = Rs. 15k

he earned 40% profit on pillows and 25% profit on bedsheets.

Cost price of pillows = 100/140 * 42k = Rs. 30k

Cost price of bedsheets = 100/125 * 63k = Rs. 50.4k

So, cost price of curtains = 100k - 30k - 50.4k = Rs. 19.6k

Loss percentage on curtains = (19.6k - 15k)/19.6k * 100 = 23.4%

Let the initial quantities of coconut oil in containers X and Y be x and y respectively.

After the first operation, container X would have 0.2x and container Y would have (0.8x + y).

After the second operation, container X would have [0.2x + 0.6(0.8x + y)] and container Y would have [0.4(0.8x + y)].

According to the question,

=> 12(x + 3(0.8x + y) = 23 * 2(0.8x + y)

=> 6(x + 2.4x + 3y) = 18.4x + 23y

=> 20.4x + 18y = 18.4x + 23y

=> 2x = 5y

=> x/y = 5/2

Hence, ratio of the initial quantity of coconut oil in containers X and Y = 5: 2

Let number of employees in IT, HR, and Admin departments are m, n, and p, respectively and total salary of employees in IT, HR, and Admin departments are X, Y, and Z, respectively.

According to the question,

X + Y = 7100(m + n) ---(1)

Y + Z = 7600(n + p) ---(2)

Z + X = 7900(m + p) ---(3)

Adding equations (1), (2), and (3), we get

2(X + Y + Z) = 15000m + 14700n + 15500p

=> X + Y + Z = 7500m + 7350n + 7750p

√(7x + 12) + √(7x - 12) = 2(4 + √10)

=> √(7x + 12) + √(7x - 12) = 8 + 2√10

=> √(7x + 12) + √(7x - 12) = √64 + √40

So, √(7x + 12) = √64 and √(7x - 12) = √40

=> 7x + 12 = 64

=> x = 52/ 7

Thus, √(14x + 21) = √(14 * 52/7 + 21) = √125 = 5√5

Let on a particular day, they make 100 cakes. So, machine A bakes 25 cakes, machine B bakes 35 cakes and machine C bakes 40 cakes respectively.

Percentage of good cakes on the next day = (25 * 0.98 + 35 * 0.96 + 40 * 0.95)/100 * 100 = 96.1%

Let amount of work done by A, B, and C alone in a day are a units, b units, and c units, respectively.

Ratio of efficiency of A and C is 5: 2.

Let a = 5k units, and C = 2k units

Now, a, b, and c are in H.P.

So, 2/b = 1/a + 1/c

=> 2/b = 1/5k + 1/2k

=> b = 20k/7

A worked for 16 days, B worked for 14 days and C worked for 18 days.

So, total unit of work = 16 * 5k + 14 * 20k/7 + 18 * 2k = 156k units

Total work done by A and B in = 156k/(5k + 20k/7) = 19(47/55) days

Sum = Rs. M; In 3 years, amount = Rs. 27M

Let rate of interest = k%;

So, M(1 + k/100)³ = 27M

=> (1 + k/100)³ = 27

=> 1 + k/100 = 3

=> k = 200%

Now, compounding half yearly, the amount will be = M(1 + 100/100)⁶ = M * 2⁶ = Rs. 64M

Hence, additional amount received = 64M - 27M = Rs. 37M

The profit of Madhav during the last month of the 1^st year = 5000 + (12 − 1) 200 = Rs. 7200

The profit of Madhav during the last month of the second year = Rs. [7200 + 11(400)] = Rs. 11600

The profit of Madhav during the last month of the third year = 11600 + 11 (600) = Rs. 18200

Hence, total salary the person has earned in four years: