Playing with Numbers Test

Result

Playing with Numbers Test - 10

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Weekly Quiz Competition

Question 1
1 / -0

If the number is divisible by $$5$$, then its last digit will be

A
$$2$$ or $$1$$

B
$$3$$

C
$$4$$

D
$$5$$ or $$0$$

Solution

According to the divisibility test of $$5$$ if a number is divisible by $$5$$ then its unit's place digit will be $$0$$ or $$5.$$

Hence, option $$D$$ is correct.
Question 2
1 / -0

Among the following options, the largest number exactly divisible by $$5$$?

A
$$60$$

B
$$25$$

C
$$95$$

D
$$97$$

Solution

We know the divisibility rule for $$5$$: The last two digits ends with $$0$$ or $$5$$.
Here, all the numbers are divisible by $$5$$ as the last digits are $$0, 5$$.
But, $$95$$ is the correct answer, as it is divisible by $$5$$ and is the largest number.
So, option C is correct.
Question 3
1 / -0

Among the following numbers, find the number which is divisible by $$10$$.

A
$$219$$

B
$$345$$

C
$$570$$

D
$$289$$

Solution

We know the divisibility rule for $$10$$ : The last digit must end with $$0$$.
Here, $$570$$ is divisible by $$10$$, since the last digit ends with $$0$$.
So, option C is correct.
Question 4
1 / -0

Among the following numbers, find the number which is divisible by $$10$$.

A
$$308$$

B
$$120$$

C
$$764$$

D
$$982$$

Solution

We know the divisibility rule for $$10$$: The last digit is $$0$$
Here, $$120$$ is divisible by $$10$$.
Since the last digit is $$0$$.
So, option B is correct.
Question 5
1 / -0

Express the number into general form: $$753$$

A
$$7 \times 10 + 5 \times 100 + 3$$

B
$$7 \times 100 + 5 \times 10 - 3$$

C
$$7 \times 100 + 5 \times 10 + 3$$

D
$$7 \times 100 + 5 \times 10 + 1$$

Solution

The general form of any three digit number is, $$abc = a \times 100 + b \times 10 + c$$
So, $$753 = 7 \times 100 + 5 \times 10 + 3$$
So, option C is correct.
Question 6
1 / -0

Express the number in expanded form: $$68$$

A
$$6 \times 10 + 8$$

B
$$60 \times 10 + 8$$

C
$$6 + 8 \times 10$$

D
$$8 \times 10 + 60$$

Solution

The general form of any two digit number will be, $$ab = a \times 10 + b$$
So, $$68 = 6 \times 10 + 8$$
So, option A is correct.
Question 7
1 / -0

Expanded form of $$640$$ is

A
$$6 \times 100 + 4 \times 10 + 0$$

B
$$5 \times 100 - 4 \times 10 - 2$$

C
$$6 \times 10 + 2 \times 10 + 2$$

D
$$7 \times 100 + 9 - 1 \times 20$$

Solution

The general form of any three digit number is, $$abc = a \times 100 + b \times 10 + c$$
So, $$640 =6 \times 100 + 4 \times 10 + 0$$
So, option A is correct.
Question 8
1 / -0

Write the number whose expanded form is as given:
$$3 \times 100 + 3 \times 10 + 3$$.

A
$$303$$

B
$$333$$

C
$$330$$

D
$$300$$

Solution

The general form of any three digit number is, $$abc = a \times 100 + b \times 10 + c$$
Here, $$ 3 \times 100 + 3 \times 10 + 3 =300+30+3 = 333 $$
So, option B is correct.
Question 9
1 / -0

Find the number in general form: $$875$$

A
$$8 \times 10 + 7 \times 10 + 5$$

B
$$8 \times 100 + 7 \times 10 + 5$$

C
$$8 \times 100 + 7 \times 100 + 5$$

D
$$8 \times 100 + 7 \times 10 + 50$$

Solution

The general form of any three digits numbers is, $$abc = a \times 100 + b \times 10 + c$$
So, $$875 = 8 \times 100 + 7 \times 10 + 5$$
So, option B is correct.
Question 10
1 / -0

If the sum of the digits of a number is divisible by $$3$$, then the number is also divisible by __.

A
$$2$$

B
$$3$$

C
$$4$$

D
$$5$$

Solution

If the sum of the digits of a number is divisible by $$3$$, then the number is also divisible by $$3$$.
Example: $$372$$
Sum of the digits $$= 3 + 7 + 2 = 12,$$ which is divisible by $$3$$.
The number, $$372$$ is also divisible by $$3$$.

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Re-Attempt Weekly Quiz Competition

Playing with Numbers Test - 10

Result

Playing with Numbers Test - 10

Score

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Rank

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SHARING IS CARING

Question 1

$$2$$ or $$1$$

$$3$$

$$4$$

$$5$$ or $$0$$

Solution

Question 2

$$60$$

$$25$$

$$95$$

$$97$$

Solution

Question 3

$$219$$

$$345$$

$$570$$

$$289$$

Solution

Question 4

$$308$$

$$120$$

$$764$$

$$982$$

Solution

Question 5

$$7 \times 10 + 5 \times 100 + 3$$

$$7 \times 100 + 5 \times 10 - 3$$

$$7 \times 100 + 5 \times 10 + 3$$

$$7 \times 100 + 5 \times 10 + 1$$

Solution

Question 6

$$6 \times 10 + 8$$

$$60 \times 10 + 8$$

$$6 + 8 \times 10$$

$$8 \times 10 + 60$$

Solution

Question 7

$$6 \times 100 + 4 \times 10 + 0$$

$$5 \times 100 - 4 \times 10 - 2$$

$$6 \times 10 + 2 \times 10 + 2$$

$$7 \times 100 + 9 - 1 \times 20$$

Solution

Question 8

$$303$$

$$333$$

$$330$$

$$300$$

Solution

Question 9

$$8 \times 10 + 7 \times 10 + 5$$

$$8 \times 100 + 7 \times 10 + 5$$

$$8 \times 100 + 7 \times 100 + 5$$

$$8 \times 100 + 7 \times 10 + 50$$

Solution

Question 10

$$2$$

$$3$$

$$4$$

$$5$$

Solution

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