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Polynomials Test - 17

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Polynomials Test - 17
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  • Question 1
    1 / -0
    Which of the following polynomials has -$$3$$ as a zero ?
    Solution
    If $$-3$$ is a zero, then $$f(-3)=0$$   ...(where $$f$$ is the function)
    In $$(A)$$, $$f(-3) = -3-3 = -6$$
    In $$(B)$$, $$f(-3) = (-3)^2-9 = 9-9 = 0$$
    In $$(C)$$, $$f(-3) = (-3)^2-3(-3) = 9+9 = 18$$
    In $$(D)$$,$$f(-3) = (-3)^2+3 = 12$$
    Hence, option $$B$$ is correct.
  • Question 2
    1 / -0
    Zero of the polynomial $$p(x)$$ where $$p(x) = ax, a \neq  0$$ is :
    Solution
    Zeroes of the polynomial is the value of the variable for which the polynomial becomes $$0$$ i.e. $$p(x)=0$$.
    Here, $$p(x)=ax$$.
    Putting $$p(x)=0$$,  we get,
              $$ax=0$$
    or,      $$x=0$$                  $$\left( \because a\neq 0 \right) $$
    So, option $$C$$ is correct.
  • Question 3
    1 / -0
    Degree of which of the following polynomials is zero?
    Solution
    The degree of a polynomial is the highest degree of its monomials (individual terms) with non-zero coefficients. 
    For, non-zero constants, degree is zero.
    Here, $$15$$ is the only non-zero constant and thus has zero degree.
    Hence, $$B$$ is correct.
  • Question 4
    1 / -0
    Zero of the polynomial $$p (x) = cx + d$$ is :
    Solution
    Zeroes of the polynomial is the value of the variable for which the polynomial becomes $$0$$, i.e. $$p(x)=0$$.
    Here, $$p(x)=cx+d$$.
    Putting $$p(x)=0$$,  we get,
              $$cx+d=0$$
    or,      $$x=\dfrac{-d}{c}$$.
    Therefore, option $$D$$ is correct.
  • Question 5
    1 / -0
    Substitute $$x = 3$$  and find the value of the given expression
    $$x^2 -5x + 4$$ 
    Solution
    Given$$\  x=3$$
    Putting the value of $$x$$, we get,
    $$x^{ 2 }-5x+4$$
    $$=(3)^2-5(3)+4$$
    $$=9-15+4$$
    $$=13-15$$
    $$=-2$$
  • Question 6
    1 / -0
     Find the zeros of the polynomial $$3\pi x - 4$$ :
    Solution
    To find the zeroes of the polynomial means to find those values of $$x$$ for which the value of equation is zero.
    That is, $$p(x)=0$$, where $$3\pi x-4=0$$.
     $$3\pi x=4$$
    $$\implies$$ $$x=\cfrac { 4 }{ 3\pi  } $$.
    Hence, option $$A$$ is correct.
  • Question 7
    1 / -0
    If the degree of polynomial $$ p(y)$$ is $$a$$, then the maximum number of zeroes of $$p(y$$) would be:
    Solution
    We know, the number of zeroes of a polynomial is equal to or less than the degree of the polynomial.
    Hence, if the degree of the polynomial is $$a$$, then the number of zeros it can have is $$a,a-1,a-2,.......0$$, i.e. it can have $$a$$ number of zeros.
    Hence, the maximum number of zeroes is $$a$$.

    Therefore, option $$C$$ is correct.
  • Question 8
    1 / -0
    The zero of the polynomial $$p(x) = 2x + 5$$ is :
    Solution
    Zero of a polynomial is the value of the variable for which the polynomial becomes $$0$$.
    Now, $$p(x)=2x+5$$.
    For, $$p(x)=0$$,  
          $$2x+5=0$$.
    or,  $$x=\dfrac{-5}{2}$$.
    Therefore, option $$D$$ is correct.
  • Question 9
    1 / -0
    8 is a polynomial of degree :
    Solution
    Degree of a polynomial is the highest power of the variable in the polynomial.
    Degree of $$8$$ is $$0$$ since $$8x^0$$$$=8$$.
  • Question 10
    1 / -0
    Degree of a constant polynomial is
    Solution
    $$\textbf{Step -1: Define constant polynomial.}$$
                     $$\text{A polynomial having no variables and only constant values is called a constant polynomial.}$$
                     $$\text{For example.- }f(x) = 8, g(k) = -10$$
                     $$\therefore \text{A constant polynomial has its highest degree as 0.}$$

    $$\textbf{Hence,  degree of constant polynomial is 0. (Option B)}$$
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