Triangles Test ...

It is given that $$AB=BC$$ and $$AD=EC.$$ The $$\triangle ABE\cong \triangle  CBD$$ by __________ congruency.

In the figure, $$\displaystyle \Delta ABC\cong \Delta ADC$$ by the congruence postulate

In the figure, $$\displaystyle AD\parallel BC$$ and $$\displaystyle AD=BC$$. Then $$\displaystyle \Delta ABD\cong \Delta CDB$$ by congruence postulate.

In the above figure, $$\angle{B}=\angle{C}=65^\circ$$ and $$\angle{D}=30^\circ$$. Then

If $$\overline{AC}$$ and $$\overline{BD}$$ intersect at $$O$$ such that $$AO = CO$$ and $$BO = DO$$, then:

In the figure, $$\displaystyle PS=QR$$ and $$PQ=SR$$, then choose the correct option.

In $$\displaystyle \Delta ABC$$ and $$\displaystyle \Delta DBC,AC=BD$$ and $$\displaystyle \angle ABC=\angle BCD={ 90 }^{ o }$$. Then $$\displaystyle \Delta ABC\cong \Delta DCB$$ by the postulate

In  $$ \displaystyle \bigtriangleup ABC,AD\perp BC,\angle B=\angle C $$ and AB = AC State by which property $$ \displaystyle \Delta ADB\cong \Delta ADC$$ ?

The two quadrilaterals are congruent.
Which angle in quadrilateral WXYZ corresponds to $$\displaystyle \angle BCD$$ in quadrilateral ABCD?

In $$\displaystyle \Delta ABC,\angle A={ 12 }^{ o }$$ and $$\angle C={ 97 }^{ o }$$. Arranging the sides (according to lengths) in ascending order, we get: