Miscellaneous Test

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Miscellaneous Test - 9

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Weekly Quiz Competition

Question 1
4 / -1

By using Newton-Raphson method, the root of x⁴ - x -10 = 0 , which is nearer to x = 2, correct to three places of decimal, is

A
2.021

B
1.856

C
1.956

D
1.586
Question 2
4 / -1

A
8 x

B
6 x

C
5 x²

D
6 x²
Question 3
4 / -1

In the usual, notation, the value of ∆ ∇ is equal to

A
∆ -∇

B
∆ +∇

C
∇ - ∆

D
None of these
Question 4
4 / -1

By the False position method, the root of the equation x³ - 9x +1= 0 lies in the interval (2, 4) after first iteration. It is

A
3

B
2.5

C
3.57

D
2.47
Question 5
4 / -1

If f (x) = a,a ∈ R, then

A
∇ f (x) = 0

B
∇ f (x) = a

C
∇ f (x) = 2a

D
∇ f (x) = a²
Question 6
4 / -1

∆² (3e ^x )is equal to

A
3e ^x

B
3(h - 1)e ^x

C
3(e ^h - 1)²e ^x

D
None of these
Question 7
4 / -1

If f (1) = 10 and f (2) = 14, then using Newton's forward formula f (1.3) is equal to

A
12.2

B
11.2

C
10.2

D
15.2
Question 8
4 / -1

The vertex connectivity of any tree is

A
one

B
two

C
three

D
None of the above
Question 9
4 / -1

In the group G = {l, 2, 3, 4, 5, 6} under ⊗₇ , the solution of 4 ⊗₇ x = 5 is

A
3

B
2

C
4

D
5
Question 10
4 / -1

In the group G = {0,1, 2, 3, 4, 5} under addition modulo 6, (2 +₆ 3^-1 +₆ 4)^-1 is equal to

A
2

B
3

C
5

D
0

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Re-Attempt Weekly Quiz Competition

Miscellaneous Test - 9

Result

Miscellaneous Test - 9

Score

-

Rank

-

SHARING IS CARING

Question 1

2.021

1.856

1.956

1.586

Question 2

8 x

6 x

5 x2

6 x2

Question 3

∆ -∇

∆ +∇

∇ - ∆

None of these

Question 4

3

2.5

3.57

2.47

Question 5

∇ f (x) = 0

∇ f (x) = a

∇ f (x) = 2a

∇ f (x) = a2

Question 6

3e x

3(h - 1)e x

3(e h - 1)2e x

None of these

Question 7

12.2

11.2

10.2

15.2

Question 8

one

two

three

None of the above

Question 9

3

2

4

5

Question 10

2

3

5

0

User

Question Analysis

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Score

-

Rank

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5 x²

6 x²

∇ f (x) = a²

3e ^x

3(h - 1)e ^x

3(e ^h - 1)²e ^x