Conic Section T...

If the parabola y² passes through the point (1, –2), then the tangent at this point is

The equation of the tangent to the parabola y² = 16x, which is perpendicular to the line y = 3x + 7 is

The line x – y + 2 = 0 touches the parabola y² = 8x at the point

The tangent to the parabola y² = 4ax at the point (a, 2a) makes with x-axis an angle equal to

The coordinates of a moving point P are (2t² + 4, 4t + 6). Then its locus will be

The equation of the tangent to the parabola y² = 9x which goes through the point (4, 10) is
a. x + 4y + 1 = 0
b. 9x + 4y + 4 = 0
c. x – 4y + 36 = 0
d. 9x – 4y + 4 = 0