Electrostatics ...

A parallel plate condenser is filled with two dielectric as shown. Area of each plate is A metre² and the separation is t metre. The dielectric constants are k₁ and k₂ respectively. Its capacitance in farad will be

Three condensers each of capacitance 2F are put in series. The resultant capacitance is

Two condensers of capacities 1 µF and 2 µF are connected in series and the system is charged to 120 volts. Then the P.D. on 1 µF capacitor (in volts) willbe

Four condensers are joined as shown in the adjoining figure. The capacity of each is 8µF. The equivalent capacity between the points A and B will be

The capacities and connection of five capacitors are shown in the adjoining figure. The potential difference between the points A and B is 60 volts. Then the equivalent capacity between A and B and the charge on 5 µF capacitance will be respectively

Four plates of the same area of cross–section are joined as shown in the figure. The distance between each plate is d. The equivalent capacity across A and B will be

In the adjoining figure, four capacitors are shown with their respective capacities and the P.D. applied. The charge and the P.D. across the 4 µF capacitor will be

Three identical capacitors are combined differently. For the same voltage to each combination, the one that stores the greatest energy is

Two capacitors each of capacity 2µF are connected in parallel. This system is connected in series with a third capacitor of 12µF capacity. The equivalent capacity of the system will be

The resultant capacitance between A and B in the following figure is equal to