Electrostatics Test

Result

Electrostatics Test - 146

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Question 1
4 / -1

Two parallel large thin metal sheets have equal surface charge densities (σ = 26.4 × 10^-12 Cm^-2) of opposite signs. The electric field between these sheets is

A
1.5 NC ^-1

B
1.5 ×10 ^-10 NC ^-1

C
3 NC ^-1

D
3 × 10 ^-10 NC ^-1

Solution
Question 2
4 / -1

A battery is used to charge a parallel plate capacitor till the potential difference between the plates becomes equal to the electromotive force of the battery. The ratio of the energy stored in the capacitor and the work done by the battery will be

A
1 : 1

B
2 : 1

C
1 : 4

D
1 : 2

Solution
Question 3
4 / -1

Capacitance of a capacitor made by a thin metal foil is 2µF. If the foil is folded with paper of thickness 0.15 mm, dielectric constant of paper is 2.5 and width of paper is 400 mm, the length of foil will be

A
0.34 m

B
1.33 m

C
13.4 m

D
33.9 m

Solution
Question 4
4 / -1

A parallel plate capacitor of capacitance 100 pF is to be constructed by using paper sheets of 1 mm thickness as dielectric. If the dielectric constant of paper is 4, the number of circular metal foils of diameter 2 cm each required for the purpose is

A
40

B
20

C
30

D
10

Solution
Question 5
4 / -1

A parallel plate condenser with oil (dielectric constant 2) between the plates has capacitance C. If oil is removed, the capacitance of capacitor becomes

A

B

C

D

Solution
Question 6
4 / -1

A sheet of aluminium foil of negligible thickness is introduced between the plates of a capacitor. The capacitance of the capacitor

A
decreases

B
remains unchanged

C
becomes infinite

D
increases

Solution
Question 7
4 / -1

Two identical capacitors each of capacitance 5 µF are charged to potentials 2 kV and 1 kV respectively. Their negative ends are connected together. When the positive ends are also connected together, the loss of energy of the system is

A
160 J

B
zero

C
5 J

D
1.25 J

Solution
Question 8
4 / -1

A dielectric of dielectric constant K is introduced such that half of its area of a capacitor of capacitance C is occupied by it. The new capacity is

A
2C

B

C

D
2C (1+K)

Solution
Question 9
4 / -1

An automobile spring extends 0.2 m for 5000 N load. The ratio of potential energy stored in this spring when it has been compressed by 0.2 m to the potential energy stored in a 10µF capacitor at a potential difference of 10000 V will be

A
1/4

B
1

C
1/2

D
2

Solution
Question 10
4 / -1

In a capacitor of capacitance 20 µF , the distance between the plates is 2 mm. If a dielectric slab of width 1 mm and dielectric constant 2 is inserted between the plates, then the new capacitance will be

A
22 µF

B
26.6 µF

C
52.2 µF

D
13 µF

Solution