Electrostatics Test

Result

Electrostatics Test - 48

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Weekly Quiz Competition

Question 1
4 / -1

Three infinitely long charge sheets are placed as shown in figure. The electric field at point P is

A

B

C

D

Solution
Question 2
4 / -1

Top of the stratosphere has an electric field E (in units of V/m) nearly equal to

A
0

B
10

C
100

D
1000
Question 3
4 / -1

Infinite charges of magnitude q each lying at x = 1, 2, 4, 8…. metre on X-axis. The value of intensity of electric field at point x = 0 due to these charges will be

A
12 × 10⁹ q N/C

B
Zero

C
6 × 10⁹ q N/C

D
4 × 10⁹ q N/C

Solution
Question 4
4 / -1

A square of side \'a\' has charge Q at its centre and charge `q\' at one of the corners. The work required in moving the charge \'q\' from one corner to the diagonally opposite corner is

A
Zero

B

C

D

Solution
Question 5
4 / -1

A pendulum bob of mass 30.7 × 10^–6 kg and carrying a charge 2 × 10^–8 C is at rest in a horizontal uniform electric field of 20000 V/m. The tension in the thread of the pendulum is (g = 9.8 m/s²)

A
3 × 10^–4 N

B
40 × 10^–4 N

C
5 × 10^–4 N

D
6 × 10^–4 N

Solution
Question 6
4 / -1

An infinite line charge produce a field of 7.182 × 10⁸ N/C at a distance of 2 cm. The linear charge density is

A
7.27 × 10^–4 C/m

B
7.98 × 10^–4 C/m

C
7.11 × 10^–4 C/m

D
7.04 × 10^–4 C/m

Solution
Question 7
4 / -1

Two thin wire rings each having a radius R are placed at a distance d apart with their axes coinciding. The charges on the two rings are +q and –q. The potential difference between the centres of the two rings is

A
Zero

B

C

D

Solution
Question 8
4 / -1

A
Positive

B
Negative

C
Zero

D
Depends on the path connecting the initial and final positions
Question 9
4 / -1

A charged ball B hangs from a silk thread S, which makes an angle θ with a large charged conducting sheet P, as shown in the figure. The surface charge density a of the sheet is proportional to

A
sin θ

B
tan θ

C
cos θ

D
cot θ

Solution
Question 10
4 / -1

Two point charges +8q and –2q are located at x = 0 and x = L respectively. The location of a point on the x-axis at which the net electric field due to these two point charge is zero is

A
8L

B
4 L

C
2 L

D
L/4

Solution