Electrostatics ...

Gauss\'s law should be invalid if

A sphere of radius R has a uniform distribution of electric charge in its volume. At a distance x from its centre, for x < R, the electric field is directly proportional to

If the electric flux entering and leaving an enclosed surface respectively is ɸ₁ and ɸ₂ the electric charge inside the surface will be

What about Gauss\'s theorem is not incorrect?

Consider the charge configuration and spherical Gaussian surface as shown in the figure. When calculating the flux of the electric field over the spherical surface the electric field will be due to

The electric flux for Gaussian surface A that enclose the charged particles in free space is (given q₁ = –14 nC, q₂ = 78.85 nC, q₃ = –56 nC)

A point charge causes an electric flux of –1.0 × 10³ Nm² C^–1 to pass through a spherical Gaussian surface of 10.0 cm radius centered on the charge. If the radius of the Gaussian surface were three times, how much flux would pass through the surface

The electric charges are distributed in a small volume. The flux of the electric field through a spherical surface of radius 10 cm surrounding the total charge is 20 Vm. The flux over a concentric sphere of radius 20 cm will be

Which of the following is the correct statement of Gauss\'s law for electrostatics in a region of charge distribution in free space

The electrostatic potential inside a charged spherical ball is given by ɸ = ar² + b, where r is the distance from the centre; a, b are constants. Then the charge density inside the ball is