Electrostatics Test

Result

Electrostatics Test - 57

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Question 1
4 / -1

Two large metal plates are placed parallel to each other. The inner surfaces of plates are charged by +σ and – σ (Coulomb/m²). The outer surfaces are neutral. The electric field is .... in the region between the plates and .... outside the plates.

A

B

C

D

Solution
Question 2
4 / -1

The capacitance of a spherical condenser is 1 µF. If the spacing between the two spheres is 1 mm, then the radius of the outer sphere is

A
30 cm

B
6 m

C
5 cm

D
3 m

Solution
Question 3
4 / -1

A 500 µF capacitor is charged at a steady rate of 100 µC/ Second. The potential difference across the capacitor will be 10 V after an interval of

A
5 sec

B
25 sec

C
20 sec

D
50 sec

Solution
Question 4
4 / -1

The capacity of a parallel plate capacitor increases with the

A
Decrease of its area

B
Increase of its distance

C
Increase of its area

D
None of the above

Solution
Question 5
4 / -1

Two parallel plate of area A are separated by two different dielectrics as shown in figure. The net capacitance is

A

B

C

D

Solution
Question 6
4 / -1

Can a metal be used as a medium for dielectric

A
Yes

B
No

C
Depends on its shape

D
Depends on dielectric
Question 7
4 / -1

The respective radii of the two spheres of a spherical condenser are 12 cm and 9 cm. The dielectric constant of the medium between them is 6. The capacity of the condenser will be

A
240 pF

B
240 µF

C
240 F

D
None of these

Solution
Question 8
4 / -1

A capacitor of capacitance value 1 µF is charged to 30 V and the battery is then disconnected. If it is connected across a 2 µF capacitor, the energy lost by the system is

A
300 µJ

B
450 µJ

C
225 µJ

D
150 µJ

Solution
Question 9
4 / -1

The energy stored in the capacitor as shown in the figure (a) is 4.5 × 10^–6 J. If the battery is replaced by another capacitor of 900 pF as shown in figure (b), then the total energy of system is

A
4.5 × 10^–6 J

B
2.25 × 10^–6 J

C
Zero

D
9 × 10^–6 J

Solution
Question 10
4 / -1

A capacitor of capacity C has charge Q and stored energy is W. If the charge is increased to 2Q, the stored energy will be

A
2W

B
W/2

C
4W

D
W/4

Solution