Electrostatics Test

Result

Electrostatics Test - 58

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Question 1
4 / -1

Between the plates of a parallel plate condenser, a plate of thickness t₁ and dielectric constant k₁ is placed. In the rest of the space, there is another plate of thickness t₂ and dielectric constant k₂. The potential difference across the condenser will be

A

B

C

D

Solution
Question 2
4 / -1

A cylindrical capacitor has charge Q and length L. If both the charge and length of the capacitor are doubled, by keeping other parameters fixed, the energy stored in the capacitor

A
Remains same

B
Increases two times

C
Decreases two times

D
Increases four times

Solution
Question 3
4 / -1

64 identical spheres of charge q and capacitance C each are combined to form a large sphere. The charge and capacitance of the large sphere is

A
64q, C

B
16q, 4C

C
64 q, 4C

D
16 q, 64 C

Solution
Question 4
4 / -1

C, V, U and Q are capacitance, potential difference, energy stored and charge of parallel plate capacitor respectively. The quantities that increases when a dielectric slab is introduced between the plates without disconnecting the battery are

A
V and C

B
V and U

C
U and Q

D
V and Q

Solution
Question 5
4 / -1

There is an air filled 1pF parallel plate capacitor. When the plate separation is doubled and the space is filled with wax, the capacitance increase to 2pF. The dielectric constant of wax is

A
2

B
4

C
6

D
8

Solution
Question 6
4 / -1

The capacity and the energy stored in a parallel plate condenser with air between its plates are respectively C₀ and W₀. If the air is replaced by glass (dielectric constant = 5) between the plates, the capacity of the plates and the energy stored in it will respectively be

A

B

C

D

Solution
Question 7
4 / -1

Force of attraction between the plates of a parallel plate capacitor is

A

B

C

D

Solution
Question 8
4 / -1

A capacitor of capacity C is connected with a battery of potential V in parallel. The distance between its plates is reduced to half at once, assuming that the charge remains the same. Then to charge the capacitance upto the potential V again, the energy given by the battery will be

A

B

C

D

Solution
Question 9
4 / -1

A 6 µF capacitor is charge from 10 volts to 20 volts. Increase in energy will be

A
18 × 10^–4 J

B
9 × 10^–4 J

C
4.5 × 10^–4 J

D
9 × 10^–6 J

Solution
Question 10
4 / -1

As shown in the figure, a very thin sheet of aluminum is placed in between the plates of the condenser. Then the capacity

A
Will increase

B
Will decrease

C
Remains unchanged

D
May increase or decrease

Solution