Electrostatics Test

Result

Electrostatics Test - 97

Score
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TIME Taken - -

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Weekly Quiz Competition

Question 1
4 / -1

A
E along KO

B
3E along OK

C
3E along KO

D
E along OK
Question 2
4 / -1

In Millikan\'s oil drop experiment an oil drop carrying a charge Q is held stationary by a potential difference 2400 V between the plates. To keep a drop of half the radius between the plates. To keep a drop of half the radius stationary the potential difference had to be made 600V
What is the charge on the second drop?

A

B

C
Q

D

Solution
Question 3
4 / -1

A charge of 5C experience a force of 5000 N when it is kept in a uniform electric field. What is the potential difference between two points separated by a distance of 1 cm?

A
10 V

B
250 V

C
1000 V

D
2500 V

Solution
Question 4
4 / -1

Two insulated charged conducting spheres of radii 20 cm and 15 cm respectively and having an equal charge of 10 C are connected by a copper wire and then they are separated. Then

A
Both the spheres will have the same charge of 10 C

B
Surface charge density on the 20 cm sphere will be greater than that on the 15 cm sphere

C
Surface charge density on the 15 cm sphere will be greater than that on the 20 cm sphere

D
Surface charge density on the two spheres will be equal

Solution
Question 5
4 / -1

Equal charges q are placed at the vertices A and B of an equilateral triangle ABC of side a. The magnitude ofelectric field at the point C is

A

B

C

D

Solution
Question 6
4 / -1

Two equal charges q are placed at a distance of 2a and a third charge –2q is placed at the midpoint. The potential energy of the system is

A

B

C

D

Solution
Question 7
4 / -1

A

B

C

D

Solution
Question 8
4 / -1

The unit of intensity of electric field is

A
Newton/Coulomb

B
Joule/Coulomb

C
Volt-metre

D
Newton/metre
Question 9
4 / -1

The electric potential at a point in free space due to a charge Q coulomb is Q × 10¹¹volts. The electric field atthe point is

A

B

C

D

Solution
Question 10
4 / -1

A charge of 5C is given a displacement of 0.5 m. The work done in the process is 10J. The potential difference between the two points will be

A
2V

B
0.25V

C
1V

D
25V

Solution