Mechanical Properties of Solids Test

Result

Mechanical Properties of Solids Test - 21

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Question 1
4 / -1

The area of cross-section of a steel wire (Y = 2.0 × 10¹¹ N/m²) is 0.1 cm². The force required to double its length will be

A
2 × 10¹² N

B
2 × 10¹¹ N

C
2 × 10¹⁰ N

D
2 × 10⁶ N

Solution
Question 2
4 / -1

Two identical wires of rubber and iron are stretched by the same weight, then the number of atoms in the iron wire will be

A
Equal to that of rubber

B
Less than that of the rubber

C
More than that of the rubber

D
None of the above
Question 3
4 / -1

Two wires A and B are of same materials. Their lengths are in the ratio 1 : 2 and diameters are in the ratio 2 : 1 when stretched by force F_A and F_B respectively they get equal increase in their lengths. Then the ratio F_A/F_B should be

A
1 : 2

B
1 : 1

C
2 : 1

D
8 : 1

Solution
Question 4
4 / -1

After effects of elasticity are maximum for

A
Glass

B
Quartz

C
Rubber

D
Metal
Question 5
4 / -1

A force of 200 N is applied at one end of a wire of length 2 m and having area of cross-section 10² cm^–2. The other end of the wire is rigidly fixed. If coefficient of linear expansion of the wire a= 8 × 10^–6/°C and Young\'s modulus Y = 2.2 × 10¹¹ N/m² and its temperature is increased by 5°C, then the increase in the tension of the wire will be

A
4.2 N

B
4.4 N

C
2.4 N

D
8.8 N

Solution
Question 6
4 / -1

A uniform plank of Young\'s modulus Y is moved over a smooth horizontal surface by a constant horizontal force F. The area of cross section of the plank is A. The compressive strain on the plank in the direction of the force is

A
F/AY

B
2F/AY

C
1/2 (F/AY)

D
3F/AY

Solution
Question 7
4 / -1

The length of a wire is 1.0 m and the area of cross-section is 1.0 × 10^–2 cm². If the work done for increase in length by 0.2 cm is 0.4 J, then Young\'s modulus of the material of the wire is

A
2.0 × 10¹⁰ N/m²

B
4.0 × 10¹⁰ N/m²

C
2.0 × 10¹¹ N/m²

D
4.0 × 10¹¹ N/m²

Solution
Question 8
4 / -1

Young\'s modulus of rubber is 104 N/m² and area of cross-section is 2 cm². If force of 2 × 10⁵ dynes is applied along its length, then its initial length L becomes

A
3L

B
4L

C
2L

D
None of these

Solution
Question 9
4 / -1

A copper wire of length 4.0 m and area of cross-section 1.2 cm² is stretched with a force of 4.8 × 10² N. If Young\'s modulus for copper is 1.2 × 10¹¹ N/m², the increase in the length of the wire will be

A
1.33 mm

B
1.33 mm

C
2.66 mm

D
2.66 mm

Solution
Question 10
4 / -1

If the interatomic spacing in a steel wire is 3.0 A and Y_steel = 20 × 10¹⁰ N/m², then force constant is

A
6 × 10^–2 N/Å

B
6 × 10^–9 N/Å

C
4 × 10^–5 N/Å

D
6 × 10^–5 N/Å

Solution