Biology Test 183

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Biology Test 183

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Weekly Quiz Competition

Question 1
4 / -1

In a cross F₁had a phenotype that did not resemble either of the two parents and was in between the two. It represents the case of :-

A
Dominance

B
Co-dominance

C
Incomplete dominance

D
Complementary gene interaction
Question 2
4 / -1

A character is controlled by 5 alleles. How many genotype are possible for this character?

A
15

B
6

C
12

D
25

Solution

Type of genotype in multiple allele system
Question 3
4 / -1

The possible blood groups of children born to the parents having A and AB blood groups are :

A
O, A

B
A, B, AB

C
O, A, B

D
O, A, B, AB
Question 4
4 / -1

Which of the following is the example of codominance ?

A
Hb^A Hb^A, I^A I^B

B
Hb^S Hb^S, I^A I^B

C
Hb^A Hb^S, I^A I^B

D
Hb^S Hb^S, I^A I^A
Question 5
4 / -1

Which one is example of polygenic inheritance?

A
ABO blood group

B
Sickle cell anaemia

C
Skin colour in human

D
Flower colour in Mirabilis jalapa
Question 6
4 / -1

ABO blood group in human there are A different allele & there are B different genotype :-

A
1

B
2

C
3

D
4
Question 7
4 / -1

Multiple alleles can be found only when :-

A
Population studies are made

B
Individual study is made

C
Mutation is absent

D
Dominance is present
Question 8
4 / -1

When more than one phenotype is influences by the same gene then dominance is not an autonomous feature of a gene. It depends upon :-

A
Gene product

B
The particular phenotype that we choose to examine.

C
Number of genes

D
Both 1 and 2
Question 9
4 / -1

When a garden pea plant with intermediate sized starch grains in seed is crossed with other plant having small sized starch grains in seed, the total number of seeds obtained in progenies is 120. What is correct for these progenies?

A
90 large size, 30 small size

B
60 large size, 60 small size

C
60 intermediate size, 60 small size

D
30 large size, 60 intermediate size, 30 small size

Solution
Question 10
4 / -1

Plant AaBbcc is of 30 cm hight while plant aabbcc is of 10 cm. Now find out maximum height of plant.

A
60 cm

B
50 cm

C
70 cm

D
Data insufficient

Solution

Plant AaBbcc - 2 dominant alleles
contribution of 1 dominant allele =

Maximum height (AABBCC) = Min Height + (total dom. alleles × contribution)
= 10 cm + ( 6 × 10 cm ) = 70 cm