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Comparing Quantities Test - 7

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Comparing Quantities Test - 7
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  • Question 1
    1 / -0
    An aluminium rod, 90 cm long, is bent to form a rectangle whose length and breadth are in respective ratio of 5 : 4. What is the area of the rectangle?
    Solution
    Let the length and breadth of the rectangle formed be 5x and 4x, respectively.
    Perimeter of rectangle = Length of the rod
    So, 2(4x + 5x) = 90
    18x = 90

    x = = 5

    Length of the rectangle = 5 × 5 = 25 cm
    Breadth of the rectangle = 4 × 5 = 20 cm
    Area of rectangle = 25 x 20 = 500 cm2
  • Question 2
    1 / -0
    Mohit bought a water dispenser that can hold 10 litres of water. What percentage of total capacity of the water dispenser is 600 cm3?
    Solution
    1 litre = 1000 cm3
    10 litres = 10,000 cm3

    Now, let the percentage be x.
    Then,
    x% of 10,000 = 600

    × 10,000 = 600

    100x = 600

    x = 6
    Therefore, 600 cm3 is 6 percent of 10 litres.
    Hence, option 2 is correct.
  • Question 3
    1 / -0
    If 120% of a number is 24000, then what is the number?
    Solution
    Let the number be x.

    120% of x = 24000

    (120/100) × x = 24000

    x = = 20000
  • Question 4
    1 / -0
    Which among the following is not equal to 4.5%?
    Solution
    Let us consider all the options:

    Option 1: × 100 = 4.5%

    Option 2: × 100 = 4.5%

    Option 3: × 100 = 45%

    Option 4: × 100 = 4.5%

    Since the value in option 3 is not 4.5, option 3 is correct.
  • Question 5
    1 / -0
    Various steps involved in finding x : y, if=, are given as options. Which of the options represents the third step?
    Solution
    Given,=

    Step 1: 3 × (3x + 2y) = 4 × (2x + 4y)

    Step 2: 9x + 6y = 8x + 16y

    Step 3: 9x - 8x = 16y - 6y

    Step 4: x = 10y

    Hence, option 2 represents the third step.
  • Question 6
    1 / -0
    The ratio of the length of ribbon P to that of ribbon Q is 2 : 3 and the ratio of the length of ribbon Q to that of ribbon R is 5 : 6. If the length of the longest of the three ribbons is 45 cm, then find the total length of all three ribbons.
    Solution
    Let the lengths of ribbon P and ribbon Q be 2x and 3x, respectively.

    Given:

    Length of ribbon R = x Length of ribbon Q

    Length of ribbon R = × 3x =

    Since ribbon R is the longest ribbon, x can be calculated as

    = 45

    x = = 12.5

    Length of ribbon P = 2x = 2 × 12.5 = 25 cm
    Length of ribbon Q = 3x = 3 × 12.5 = 37.5 cm
    Length of ribbon R (longest) = 45 cm
    Total length of all three ribbons = 25 + 37.5 + 45 = 107.5 cm
  • Question 7
    1 / -0
    What value should come in place of the question mark (?) in the following equation?

    24% of 1680 = 36% of ?
    Solution
    24% of 1680 = 36% of ?











  • Question 8
    1 / -0
    If A exceeds B by 25%, then by what percent is B less than A?
    Solution
    Let B = 100

    Now, 25% of 100 = = 25

    Therefore, A = 100 + 25 = 125
    Percent by which B is less than A =
    = = 20%
  • Question 9
    1 / -0
    What percent of 2 days is 1080 minutes?
    Solution
    2 days = 48 hours
    1 hour = 60 minutes
    2 days = 60 × 48 = 2880 minutes

    Required % = × 100 = 37.50%
  • Question 10
    1 / -0
    10 pencils are bought for Rs. 8 and 8 of them are sold for Rs. 10. Find the gain/loss percentage in this case.
    Solution
    C.P. of 10 pencils = Rs. 8

    C.P. of 1 pencil = = Rs.

    Also, S.P. of 8 pencils = Rs. 10

    So, S.P. of 1 pencil = = Rs.

    Now, profit = S.P. – C.P.

    = - =

    Profit % = x 100 = × 100
    = 56.25%
  • Question 11
    1 / -0
    What percentage of the following figure is shaded?

    Solution
    Total number of squares = 100

    Number of shaded squares = 25

    Required percentage = × 100 = 25%
  • Question 12
    1 / -0
    Choose the INCORRECT match:

    Item S.P. (in Rs.) Profit/Loss C.P. (in Rs.)
    (A) Bottle 250 25% profit 200
    (B) Book 150 50% profit 100
    (C) Table 200 40% loss 280
    (D) Toy Car 450 25% loss 600
    Solution
    (A)
    C.P. of bottle = Rs. 200
    S.P. of bottle = Rs. 250

    Profit % = × 100

    = = 25%

    (B)
    C.P. of book = Rs. 100
    S.P. of book = Rs. 150

    Profit % = × 100

    = = 50%

    (C)
    C.P. of table = Rs. 280
    S.P. of table = Rs. 200

    Loss % = × 100

    = = 28.57% (Incorrect)

    (D)
    C.P. of toy car = Rs. 600
    S.P. of toy car = Rs. 450

    Loss % = × 100

    = = 25%
  • Question 13
    1 / -0
    The simple interest on a certain sum of money (principal) is of that sum. Find the rate of interest and time, if both are numerically equal.
    Solution
    Let P be the principal amount.
    Rate of interest = R
    Time = T
    Simple Interest = SI
    Now,

    SI =

    Now, SI = P, so

    P =

    R × R =

    R = = %

    T = years or 7 years and 6 months
  • Question 14
    1 / -0
    Express 82 m as a percentage of 2 km 50 m.
    Solution
    2 km 50 m = 2000 m + 50 m = 2050 m

    Required percentage = × 100 = 4%
  • Question 15
    1 / -0
    Two numbers are in the ratio of 3 : 2. When each number is increased by 14, the ratio becomes 5 : 4. The numbers are
    Solution
    Given Ratio = 3 : 2
    Let the numbers be 3x and 2x.
    According to question:

    =

    12x + 56 = 10x + 70
    2x = 14
    x = 7

    Therefore, the numbers are:
    3x = 3 × 7 = 21
    2x = 2 × 7 = 14
  • Question 16
    1 / -0
    In an election between two candidates, the candidate who received 40% of the votes loses by 14,000 votes. What is the total number of votes received by the winning candidate?
    Solution
    Let the total number of votes polled be x.

    Then, 40% of x + 14,000 = 60% of x

    + 14,000 =

    = 14,000

    x == 70,000

    Total number of votes polled = 70,000

    Number of votes received by the winning candidate = 60% of 70,000

    × 70,000 = 42,000
  • Question 17
    1 / -0
    A contractor employed 400 men to build a bridge in 120 days. After 20 days, they were joined by 100 more men. In how many days was the remaining work completed?
    Solution
    Let the total work be 1.

    Work done in 120 days by 400 men = 1

    Work done in 1 day by 400 men =

    Work done in 20 days by 400 men = × 20 =
    Now, of work is left for (400 + 100) = 500 workers to complete.

    Let the number of days taken by them to finish the remaining work be x.

    500 × x =× 400 × 120

    x = = 80 days
  • Question 18
    1 / -0
    A man sold two jackets for Rs. 1500 each, neither losing nor gaining in the transaction. If he sold one jacket at a profit of 20%, then he sold the other jacket at a loss of
    Solution
    Selling price of 1 jacket = Rs. 1500

    Profit % = 20%

    C.P. = = = Rs. 1250

    The man neither gains nor loses in the transaction.

    Therefore, cost price of second jacket

    = S.P. of 2 jackets - C.P. of 1 jacket

    = (3000 - 1250) = Rs. 1750

    Now, C.P. of second jacket = Rs. 1750

    Selling Price = Rs. 1500

    Loss % = =

    = = %
  • Question 19
    1 / -0
    By selling a bucket for Rs. 135, a man loses of his outlay. If it were sold for Rs. 182, what would be the gain percentage?
    Solution
    Selling price of the bucket = Rs. 135
    Let the cost of the bucket be x.
    Loss = C.P. - S.P.
    Loss = = x - 135 or 135 =
    x = Rs. 168.75
    Cost price of bucket = Rs. 168.75
    Now, profit = S.P. - C.P.
    182 - 168.75 = 13.25

    Profit % = × 100





    = 7.85%
  • Question 20
    1 / -0
    Ram purchased 100 pens for Rs. 500 and sold them for Rs. 550, while Raghav purchased 100 pens for Rs. 600 and sold them for Rs. 750. For whom is the profit percentage higher and by how much?
    Solution
    Cost price of pens purchased by Ram = Rs. 500
    S.P. = Rs. 550
    Profit of Ram = S.P. - C.P. = 550 - 500 = Rs. 50
    Profit % == 10%
    Cost price of pens purchased by Raghav = Rs. 600
    S.P. = Rs. 750
    Profit = 750 - 600 = Rs. 150
    Profit % == 25%
    Raghav's profit percentage is higher by (25 - 10) = 15%.
  • Question 21
    1 / -0
    Match the following:

    Column I Column II
    i. Atul sells his bike for Rs. 25,000 at a profit of 25%. The cost price of the bike was P. 12
    ii. Ram deposits a certain sum of money in bank at the rate of 4% for 4 years, and the interest earned is Rs. 420. Find the amount deposited by Ram. Q. 2625
    iii. The ratio of boys to girls in a classroom is 4 : 9, and the number of girls is 27. How many boys are there in the class? R. 20000
    Solution
    i. SP = Rs. 25,000
    Profit % = 25%

    Profit % =

    25% =

    25CP = 25,00,000 - 100CP
    125CP = 25,00,000
    CP = Rs. 20,000

    ii. SI = Rs. 420
    R = 4%
    T = 4 years

    = SI

    P = = Rs. 2625

    iii. Boys : Girls = 4 : 9
    Let the numbers of boys and girls be 4x and 9x, respectively.
    Now, 9x = 27.
    x = 3
    Boys = 4x = 4 x 3 = 12
  • Question 22
    1 / -0
    Determine whether the given statements are true (T) or false (F) and choose the correct option:

    I. Raghav had Rs. 12,000. He spent 25% of it on shopping and gave the rest to her mom. The amount that he gave to her mom was Rs. 8000.
    II. Sonia went to a shop and bought 56 lipsticks, 34 eyeliners and 72 combs. The shopkeeper had 100 units of each of these items. She bought 54% of the total units of all three items.
    III. Karan bought some apples for Rs. 200 and sold them for Rs. 250. His profit percentage was 25%.
    Solution
    I. Raghav had Rs. 12,000.
    He spent 25% on shopping.
    Money left after shopping = 12,000 - (12,000 x 0.25) = Rs. 9000 (False)

    II. Number of lipsticks bought = 56
    Number of eyeliners bought = 34
    Number of combs bought = 72
    Total units bought = 56 + 34 + 72 = 162
    Total number of available units = 300

    Percentage = x 100 = 54% (True)

    III. C.P. = Rs. 200
    S.P. = Rs. 250

    Profit = x 100 = 25% (True)
  • Question 23
    1 / -0
    Which of the following statements is/are correct?

    I. A sum of money is to be distributed among A, B and C in the respective ratio of 5 : 2 : 4. If C gets Rs. 1000. then B will get Rs. 550.
    II. There are 15 persons invited for an interview. Out of them, 3 decline the invitation. The percentage of persons who accept the invitation is 80%.
    Solution
    1. Let A, B and C get 5x, 2x and 4x, respectively.
    C gets Rs. 1000.
    So, 4x = 1000
    x = Rs. 250
    Therefore, B gets 2x = Rs. 250 x 2 = Rs 500 (False)

    2. Number of persons invited = 15
    Number of persons who decline = 3
    So, remaining persons = 15 - 3 = 12
    Percentage of remaining persons = x 100 = 80% (True)
  • Question 24
    1 / -0
    Directions: In this problem, a question is asked followed by three statements, numbered (i), (ii) and (iii). Read all the statements carefully and decide which of them is/are required to answer the question.

    What is the principal?

    (i) Total simple interest on the sum is Rs. 100.
    (ii) Total simple interest on the sum is Rs. 500 for 5 years.
    (iii) The rate of interest is 5% per annum.
    Solution
    Both ii and iii are required.
    Given: SI = Rs. 500
    R = 5%
    T = 5 years

    SI =



    P = Rs. 2000
  • Question 25
    1 / -0
    Fill in the blanks:

    (i) If Ankita travels 220 km in 20 hours, then she will travel ______ km in 40 hours at the same speed.
    (ii) If the cost price of a mobile is Rs. 12,000 and the selling price is Rs. 14,000, then the amount of profit will be ______.
    (iii) If the ratio of the number of males to that of females is 3 : 7 and the number of males is 21, then the number of females is _____.
    Solution
    (i) Since speed remains the same, distance is directly proportional to time.







    d2 = 440 km

    (ii) C.P. = Rs. 12,000
    S.P. = Rs. 14,000
    Profit = 14,000 - 12,000 = Rs. 2000

    (iii) Let the numbers of males and females be 3x and 7x, respectively.
    Number of males = 21
    So, 3x = 21
    x = 7
    Number of females = 7x = 7 x 7 = 49
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