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Physics Test - 8

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Physics Test - 8
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  • Question 1
    1 / -0

    A horizontal pipe of cross-sectional diameter 5 cm carries water at a velocity of 4 m/s. The pipe is connected to a smaller pipe with a cross-sectional diameter 4 cm. What is the velocity of water through the smaller pipe?

    Solution

  • Question 2
    1 / -0

    In a stationary lift, a man is standing with a bucket full of water, having a hole at its bottom. The rate of flow of water through this hole is R0. If the lift starts to move up and down with the same acceleration such that the water flows at the rate of Rand Rd, then

    Solution

  • Question 3
    1 / -0

    The water filled in a tank has a hole 'h' metres from the top. Find the distance 'x' where the stream of water will touch the ground from the bottom.

    Solution

  • Question 4
    1 / -0

    An incompressible fluid flows steadily through a cylindrical pipe which has radius '2R' at a point 'A' and radius 'R' at a point 'B'. If the velocity at point 'A' is 'v' along the flow of direction, what will be its velocity at point 'B'?

    Solution

  • Question 5
    1 / -0

    The cylindrical tube of a spray pump has a cross-section of 8 cm2, one end of which has 40 fine holes, each of area 10-8m2. If the liquid flows inside the tube with a speed of 0.15 m min-1, then the speed with which the liquid is ejected through the holes is

    Solution

  • Question 6
    1 / -0

    A small circular flexible loop of wire of radius r carries a current l. It is placed in a uniform magnetic field B. The tension in the loop will be doubled if :

    Solution

  • Question 7
    1 / -0

    Which of the following laws states that good absorbers of heat are good emitters?

    Solution

    Kirchhoff's law states that good absorbers of heat are good emitters.

  • Question 8
    1 / -0

    A can is taken out from a refrigerator at \(0^{\circ} \mathrm{C}\). The atmospheric temperature is \(25^{\circ} \mathrm{C}\). If \(\mathrm{t}_{1}\) is the time taken to heat from \(0^{\circ} \mathrm{C}\) to \(5^{\circ}\) and \(\mathrm{t}_{2}\) is the time taken from \(10^{\circ} \mathrm{C}\) to \(15^{\circ} \mathrm{C}\), then:

    Solution

    Newton's law of heating states that the rate of change of temperature of an object is proportional to the difference in temperatures of the surrounding and the object.

    In the given cases, when the initial temperature of the Can is \(0^{\circ} \mathrm{C}\), the difference in temperatures of can and surrounding is \(25-0=25^{\circ} \mathrm{C}\).

    When initial temperature of can is \(10^{\circ} \mathrm{C}\), the difference in temperatures of can and surrounding is \(25-10=15^{\circ} \mathrm{C}\). Therefore the rate of heating will be higher, when temperature difference is \(25^{\circ} \mathrm{C}\) i.e., time \(\mathrm{t}_{1}\) will be smaller than \( t_2\)(\(\mathrm{t}_{1}<\mathrm{t}_{2}\)).

  • Question 9
    1 / -0

    Black body emits the radiation of maximum intensity 5000 A0, when its temperature is 12270C. If its temperature is increased by 10000C, what is the maximum intensity of emitted radiation?

    Solution

  • Question 10
    1 / -0

    A sound wave reflected at the boundary will undergo a phase change on reflection at

    Solution

    metal - air boundary

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