Letter Series Test

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Letter Series Test - 1

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Question 1
3 / -1

A, B, D, H, ____, F

A
P

B
T

C
X

D
H

Solution

Each letter in the given series is multiplied with 2 to get the next letter in the series.
A = 1 and 1 × 2 = 2 and the 2nd letter is B.
B = 2 and 2 × 2 = 4 and the 4th letter is D.
Similarly, H = 8 and 8 × 2 = 16, and the 16th letter P is the missing letter.
So, Correct Option is Option A
Question 2
3 / -1

D, F, G, H, J, K, L, M N, ___

A
O

B
P

C
Q

D
R

Solution

D, F, G, H, J, K, L, M, N, ____
The given series consists of consonants in increasing order, starting with D.
The next consonant in the series is P.
So, Correct Option is Option B
Question 3
3 / -1

G, J, N, Q, U, ___

A
W

B
Y

C
X

D
Z

Solution

G + 3, J + 4, N + 3, Q + 4, U + 3 , _____
The next letter in the series is U + 3 = X.
So, Correct Option is Option C.
Question 4
3 / -1

BY, CX, EV, GT, KP, ____

A
MN

B
JQ

C
PK

D
LO
Solution
BY, CX, EV, GT, KP, _____
The given series is a mixed series.
The letters B, C, E, G, and K are the letters in prime value positions. Hence, the next letter is M.
The second letter in each group forms an opposite pair of the first letter in that group. Hence, the next pair in the series is MN.
Question 5
3 / -1

AP, BQ, CR, DS, ___

A
EV

B
EU

C
TE

D
ET
Solution
The first letters in all the pairs, i.e., A, B, C, and D, form a series of consecutive letters.
The second letters P, Q, R, and S form another pair of consecutive letters. Hence, The next pair in the series is ET.
Question 6
3 / -1

AI, EO, IU, ___, UE

A
OU

B
OI

C
OA

D
UA
Solution
The first letters in all the groups are consecutive vowels starting with A.
The second letters in all the groups are consecutive vowels starting with I.
Hence, the missing pair is OA.
Question 7
3 / -1

KPD, LOE, MNF, NMG, ____

A
ONF

B
MLH

C
OLH

D
MNH
Solution
The given series is a mixed series.
Pattern for the first letter:
K + 1, L + 1, M + 1, N + 1, O
Pattern for the second letter:
P – 1, O – 1, N – 1, M – 1, L
Pattern for the third letter:
D + 1, E + 1, F + 1, G + 1, H
Hence, the next group in the series is OLH.
Question 8
3 / -1

QLR, JPD, RNU, GNC, SPX, DLB, ____

A
ARE

B
TRA

C
BTU

D
AJA
Solution
The alternate groups are in mixed series.
QLR, RNU, SPX are in one series.
The Pattern for the first letter:
Q + 1, R + 1, S + 1, T
The Pattern for the second letter:
L + 2, N + 2, P + 2, R
The Pattern for the third letter:
R + 3, U + 3, X + 3, A
Hence, the next group in the series is TRA.
Question 9
3 / -1

GTB, CYV, YDP, ____, QND

A
DIV

B
UIJ

C
DDV

D
UVV
Solution
The given series is a mixed series.
Pattern for the first letter:
G – 4, C – 4, Y – 4, U – 4, Q
Pattern for the second letter:
T + 5, Y + 5, D + 5, I + 5, N
Pattern for the third letter:
B – 6, V – 6, P – 6, J – 6, D
Hence, the missing group is UIJ.
Question 10
3 / -1

2F3, 3O5, 5I7, 7Y11, ____

A
11L13

B
11J15

C
13M17

D
11M13
Solution
In each term the numbers are pairs of consecutive prime numbers.
The letter between them has the place value equal to the product of the two numbers on either side of it.
∵ The next two prime numbers are 11 and 13 whose product is 143. The 143rd letter is (26 × 5 + 13) M.
∴ 11M13 is the next term.
Question 11
3 / -1

If the first five letters of the alphabet series in the reverse order, then next six are in reverse order, then next seven letters are in reverse order, then remaining letters are in reverse order.
Q. Which letter is 5^th to the left of 12^th letter from the right hand side of the alphabet series?

A
K

B
J

C
H

D
G

Solution

When the letters are reversed in the group of Five, six, and seven letters.
5th to the left of 12^th from the right end (27- 12 = 15^th from left) means, 15 – 5 = 10^ththat lies in the 2^ndgroup(6-11).
Therefore, 6 + 11 = 17 – 10 = 7^thletter i.e. “G”.
Question 12
3 / -1

If the first five letters of the alphabet series in the reverse order, then next six are in reverse order, then next seven letters are in reverse order, then remaining letters are in reverse order.
Q. Which letter is 5^th to the right of 12^th letter from the right hand side of the alphabet series?

A
T

B
Y

C
X

D
G

Solution

When the letters are reversed in the group of Five, six, seven and letters.
5th to the right of 12th from right end (27 – 12 = 15th from left) means, 15 + 5 = 20th
Which lies in 4th group(19-26). Therefore,
19 + 26 = 45 ; 45 – 20 = 25th = “Y”.

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Re-Attempt Weekly Quiz Competition

Letter Series Test - 1

Result

Letter Series Test - 1

Score

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Rank

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SHARING IS CARING

Question 1

P

T

X

H

Solution

Question 2

O

P

Q

R

Solution

Question 3

W

Y

X

Z

Solution

Question 4

MN

JQ

PK

LO

Solution

Question 5

EV

EU

TE

ET

Solution

Question 6

OU

OI

OA

UA

Solution

Question 7

ONF

MLH

OLH

MNH

Solution

Question 8

ARE

TRA

BTU

AJA

Solution

Question 9

DIV

UIJ

DDV

UVV

Solution

Question 10

11L13

11J15

13M17

11M13

Solution

Question 11

K

J

H

G

Solution

Question 12

T

Y

X

G

Solution