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Logical Reasoning Test-3

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Logical Reasoning Test-3
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  • Question 1
    1 / -0

    Directions For Questions

    Directions: Study the following information carefully and answer the given questions:

    A word and number arrangement machine when given an input line of binary (consisting of only 1s and 0s) and decimal numbers rearranges them following a particular hide in each step. The following is an illustration of input and rearrangement. (All the numbers are two digit numbers).

    Input: 100 37 96 11001 79 88 1005 1100 1000 100001 98 10

    Step I: 10 100 37 96 11001 79 88 1100 1000 100001 98 1005

    Step II: 10 100 37 96 11001 79 88 1100 1000 100001 1005 98

    Step III: 10 100 1000 37 11001 79 88 1100 100001 1005 98 96

    Step IV: 10 100 1000 1100 37 11001 79 100001 1005 98 96 88

    Step V: 10 100 1000 1100 11001 37 100001 1005 98 96 88 79

    Step VI: 10 100 1000 1100 11001 100001 1005 98 96 88 79 37

    And Step VI is the last step of the above input, as the desired arrangement is obtained.

    As per the hides followed in the above steps, find out in each of the following questions the appropriate step for the given input.

    Input: 23 47 100 923 1001 1101 1029 32 10100 1000101 57 10

    (All the numbers are two digits numbers).

    ...view full instructions

    Which number would be at 3rd position from the left in Step IV?

    Solution

    In the given illustration:

    1) Decimal numbers are arranged in descending order.

    2) In case of binary numbers, they are arranged in ascending order.

    3) A binary and decimal number are arranged simultaneously in each step, whenever possible.

    Now,

    Given input is: 23 47 100 923 1001 1101 1029 32 10100 1000101 57 10

    Step I: 10 23 47 100 923 1001 1101 32 10100 1000101 57 1029

    Step II: 10 100 23 47 1001 1101 32 10100 1000101 57 1029 923

    Step III: 10 100 1001 23 47 1101 32 10100 1000101 1029 923 57

    Step IV: 10 100 1001 1101 23 32 10100 1000101 1029 923 57 47

    Step V: 10 100 1001 1101 10100 23 1000101 1029 923 57 47 32

    Step VI: 10 100 1001 1101 10100 1000101 1029 923 57 47 32 23

    (Left) Step IV: 10 100 1001 1101 23 32 10100 1000101 1029 923 57 47 (Right)

    Clearly, the number ‘1001’ is at 3rd position from left in step IV.

     

  • Question 2
    1 / -0

    Directions For Questions

    Directions: Study the following information carefully and answer the given questions:

    A word and number arrangement machine when given an input line of binary (consisting of only 1s and 0s) and decimal numbers rearranges them following a particular hide in each step. The following is an illustration of input and rearrangement. (All the numbers are two digit numbers).

    Input: 100 37 96 11001 79 88 1005 1100 1000 100001 98 10

    Step I: 10 100 37 96 11001 79 88 1100 1000 100001 98 1005

    Step II: 10 100 37 96 11001 79 88 1100 1000 100001 1005 98

    Step III: 10 100 1000 37 11001 79 88 1100 100001 1005 98 96

    Step IV: 10 100 1000 1100 37 11001 79 100001 1005 98 96 88

    Step V: 10 100 1000 1100 11001 37 100001 1005 98 96 88 79

    Step VI: 10 100 1000 1100 11001 100001 1005 98 96 88 79 37

    And Step VI is the last step of the above input, as the desired arrangement is obtained.

    As per the hides followed in the above steps, find out in each of the following questions the appropriate step for the given input.

    Input: 23 47 100 923 1001 1101 1029 32 10100 1000101 57 10

    (All the numbers are two digits numbers).

    ...view full instructions

    What is the difference between 6th number from left end and 4th number from right end in penultimate step?

    Solution

    In the given illustration:

    1) Decimal numbers are arranged in descending order.

    2) In case of binary numbers, they are arranged in ascending order.

    3) A binary and decimal number are arranged simultaneously in each step, whenever possible.

    Now,

    Given input is: 23 47 100 923 1001 1101 1029 32 10100 1000101 57 10

    Step I: 10 23 47 100 923 1001 1101 32 10100 1000101 57 1029

    Step II: 10 100 23 47 1001 1101 32 10100 1000101 57 1029 923

    Step III: 10 100 1001 23 47 1101 32 10100 1000101 1029 923 57

    Step IV: 10 100 1001 1101 23 32 10100 1000101 1029 923 57 47

    Step V: 10 100 1001 1101 10100 23 1000101 1029 923 57 47 32

    Step VI: 10 100 1001 1101 10100 1000101 1029 923 57 47 32 23

    Therefore in step V (The penultimate step) the 6th element from the left is 23 and the 4th element from the right is 923.

    Therefore the difference is 900.

     

  • Question 3
    1 / -0

    Directions For Questions

    Directions: Study the following information carefully and answer the given questions:

    A word and number arrangement machine when given an input line of binary (consisting of only 1s and 0s) and decimal numbers rearranges them following a particular hide in each step. The following is an illustration of input and rearrangement. (All the numbers are two digit numbers).

    Input: 100 37 96 11001 79 88 1005 1100 1000 100001 98 10

    Step I: 10 100 37 96 11001 79 88 1100 1000 100001 98 1005

    Step II: 10 100 37 96 11001 79 88 1100 1000 100001 1005 98

    Step III: 10 100 1000 37 11001 79 88 1100 100001 1005 98 96

    Step IV: 10 100 1000 1100 37 11001 79 100001 1005 98 96 88

    Step V: 10 100 1000 1100 11001 37 100001 1005 98 96 88 79

    Step VI: 10 100 1000 1100 11001 100001 1005 98 96 88 79 37

    And Step VI is the last step of the above input, as the desired arrangement is obtained.

    As per the hides followed in the above steps, find out in each of the following questions the appropriate step for the given input.

    Input: 23 47 100 923 1001 1101 1029 32 10100 1000101 57 10

    (All the numbers are two digits numbers).

    ...view full instructions

    Which step number is the following output?

    10 100 1001 23 47 1101 32 10100 1000101 1029 923 57

    Solution

    In the given illustration:

    1) Decimal numbers are arranged in descending order.

    2) In case of binary numbers, they are arranged in ascending order.

    3) A binary and decimal number are arranged simultaneously in each step, whenever possible.

    Now,

    Given input is: 23 47 100 923 1001 1101 1029 32 10100 1000101 57 10

    Step I: 10 23 47 100 923 1001 1101 32 10100 1000101 57 1029

    Step II: 10 100 23 47 1001 1101 32 10100 1000101 57 1029 923

    Step III: 10 100 1001 23 47 1101 32 10100 1000101 1029 923 57

    Step IV: 10 100 1001 1101 23 32 10100 1000101 1029 923 57 47

    Step V: 10 100 1001 1101 10100 23 1000101 1029 923 57 47 32

    Step VI: 10 100 1001 1101 10100 1000101 1029 923 57 47 32 23

    Therefore, it is step III.

     

  • Question 4
    1 / -0

    Directions For Questions

    Directions: Study the following information carefully and answer the given questions:

    A word and number arrangement machine when given an input line of binary (consisting of only 1s and 0s) and decimal numbers rearranges them following a particular hide in each step. The following is an illustration of input and rearrangement. (All the numbers are two digit numbers).

    Input: 100 37 96 11001 79 88 1005 1100 1000 100001 98 10

    Step I: 10 100 37 96 11001 79 88 1100 1000 100001 98 1005

    Step II: 10 100 37 96 11001 79 88 1100 1000 100001 1005 98

    Step III: 10 100 1000 37 11001 79 88 1100 100001 1005 98 96

    Step IV: 10 100 1000 1100 37 11001 79 100001 1005 98 96 88

    Step V: 10 100 1000 1100 11001 37 100001 1005 98 96 88 79

    Step VI: 10 100 1000 1100 11001 100001 1005 98 96 88 79 37

    And Step VI is the last step of the above input, as the desired arrangement is obtained.

    As per the hides followed in the above steps, find out in each of the following questions the appropriate step for the given input.

    Input: 23 47 100 923 1001 1101 1029 32 10100 1000101 57 10

    (All the numbers are two digits numbers).

    ...view full instructions

    How many elements (words or numbers) are there between ‘1101’ and ‘1000101’ as they appear in the penultimate step of the output?

    Solution

    In the given illustration:

    1) Decimal numbers are arranged in descending order.

    2) In case of binary numbers, they are arranged in ascending order.

    3) A binary and decimal number are arranged simultaneously in each step, whenever possible.

    Now,

    Given input is: 23 47 100 923 1001 1101 1029 32 10100 1000101 57 10

    Step I: 10 23 47 100 923 1001 1101 32 10100 1000101 57 1029

    Step II: 10 100 23 47 1001 1101 32 10100 1000101 57 1029 923

    Step III: 10 100 1001 23 47 1101 32 10100 1000101 1029 923 57

    Step IV: 10 100 1001 1101 23 32 10100 1000101 1029 923 57 47

    Step V: 10 100 1001 1101 10100 23 1000101 1029 923 57 47 32

    Step VI: 10 100 1001 1101 10100 1000101 1029 923 57 47 32 23

    Therefore in step V there are two elements between 1101 and 1000101.

     

  • Question 5
    1 / -0

    Directions For Questions

    Directions: Study the following information carefully and answer the given questions:

    A word and number arrangement machine when given an input line of binary (consisting of only 1s and 0s) and decimal numbers rearranges them following a particular hide in each step. The following is an illustration of input and rearrangement. (All the numbers are two digit numbers).

    Input: 100 37 96 11001 79 88 1005 1100 1000 100001 98 10

    Step I: 10 100 37 96 11001 79 88 1100 1000 100001 98 1005

    Step II: 10 100 37 96 11001 79 88 1100 1000 100001 1005 98

    Step III: 10 100 1000 37 11001 79 88 1100 100001 1005 98 96

    Step IV: 10 100 1000 1100 37 11001 79 100001 1005 98 96 88

    Step V: 10 100 1000 1100 11001 37 100001 1005 98 96 88 79

    Step VI: 10 100 1000 1100 11001 100001 1005 98 96 88 79 37

    And Step VI is the last step of the above input, as the desired arrangement is obtained.

    As per the hides followed in the above steps, find out in each of the following questions the appropriate step for the given input.

    Input: 23 47 100 923 1001 1101 1029 32 10100 1000101 57 10

    (All the numbers are two digits numbers).

    ...view full instructions

    Which of the following represents the position of ‘32’ in the third step?

    Solution

    In the given illustration:

    1) Decimal numbers are arranged in descending order.

    2) In case of binary numbers, they are arranged in ascending order.

    3) A binary and decimal number are arranged simultaneously in each step, whenever possible.

    Now,

    Given input is: 23 47 100 923 1001 1101 1029 32 10100 1000101 57 10

    Step I: 10 23 47 100 923 1001 1101 32 10100 1000101 57 1029

    Step II: 10 100 23 47 1001 1101 32 10100 1000101 57 1029 923

    Step III: 10 100 1001 23 47 1101 32 10100 1000101 1029 923 57

    Step IV: 10 100 1001 1101 23 32 10100 1000101 1029 923 57 47

    Step V: 10 100 1001 1101 10100 23 1000101 1029 923 57 47 32

    Step VI: 10 100 1001 1101 10100 1000101 1029 923 57 47 32 23

    Therefore in the third step 32 is either 7th from the left or 6st from the right.

     

  • Question 6
    1 / -0

    Directions For Questions

    In the following question, a word is represented by only one set of number as given in any one of the alternative. The set of number given in the alternatives are represented by two classes of alphabets as in two matrices given below. The columns and rows Matrix - I are numbered from 0 to 4 and that of Matrix - II are numbered from 5 to 8. A letter from these matrices is to be represented first by its row and then by its column, e.g ‘B’ can be represented by 20, 12, 33, 44 etc and ‘D’ 56, 77, 89, 98 etc.

    ...view full instructions

    What is code of 'TOLD' ?

    Solution

    T→57, 69, 75, 88, 96

    O→03, 14, 22, 31, 40

    L→00, 13, 21, 34, 42

    D→56, 65,77, 89, 98

    Therefore,  the number set will be 57, 14, 21, 89.

     

  • Question 7
    1 / -0

    Direction: The question given below is followed by two arguments numbered I and II. You have to decide which of the argument is a strong argument and which is a weak argument.

    Statement: 

    Should government services be linked with academic degree and diploma?

    Arguments:

    I. No, a large number of people with meager academic qualifications will apply.

    II. No, importance of higher education will be diminished.

    Solution

    If governmental services are linked with academic degree and diploma, people with meager academic qualification will in fact not be able to apply. So, argument I does not hold.

    If governmental services are linked with academic degree and diploma, people will be motivated to pursue their education more, instead of the importance of higher education getting diminished as said by argument II. Thus, argument II does not hold. 

     

  • Question 8
    1 / -0

    Directions: In the question given below, there is a statement followed by two assumptions numbered I and II. An assumption is something supposed or taken for granted. You have to consider the statement and assumptions and then decide which of the assumption(s) is/are implicit in the statement. You have to consider the statements to be true even if they seem to be at variance from commonly known facts.

    Statement: Gambling through lotteries is banned by the central government in all the states with immediate effect.

    Assumption:

    I. This may save innocent citizens from getting cheated of their hard-earned money.

    II. The citizens may not gamble in any other way if the lotteries are banned.

    Solution

    As we see the statement, The central government order to ban gambling of lotteries because of cheating. The assumption I is implicit here because this true that innocent citizens get cheated by them and government moves are generally aimed at protecting the interests of the masses. The assumption II is not implicit here because of 'any other way'. There might be other means of gambling which the government does not consider significantly detrimental for the people. So, the assumption I is implicit here.

     

  • Question 9
    1 / -0

    Directions For Questions

    Direction: In the question below are given four statements followed by three conclusions I, II, III. You have to take the given statements to be true even if they seem to be at variance from commonly known facts. Read all the conclusions and then decide which of the given conclusions logically follows from the given statements disregarding commonly known facts.

    ...view full instructions

    Statements:

    Some japanese are chinese.

    All chinese are indians.

    No indian is mexicans.

    Some mexicans are malaysians.

    Conclusions:

    I. All japanese being mexicans is a possibility.

    II. No chinese is mexican.

    III. Some japanese are indians.

    Solution

    The least possible Venn diagram for the given statements is as follows,

    I. All japanese being mexicans is a possibility. → False (It is not possible since no indian is mexican)

    II. No chinese is mexican → True (It is possible since no indian is mexican)

    III. Some japanese are indians → True (It is possible as shown in the figure above)

    Hence, only II and III follows.

     

  • Question 10
    1 / -0

    Directions For Questions

    Direction: In the question below are given four statements followed by three conclusions I, II, III. You have to take the given statements to be true even if they seem to be at variance from commonly known facts. Read all the conclusions and then decide which of the given conclusions logically follows from the given statements disregarding commonly known facts.

    ...view full instructions

    Statements:

    All bats are lions.

    Some cats are lions.

    No cat is a tiger.

    Conclusion:

    I. Some tigers can be bats.

    II. No cat is bat.

    Solution

    The least possible diagram of this question is as follows,

    I. Some tigers can be bats → True (possibility is true)

    II. No cat is bat → False (it is possible but not definite)

    Therefore, the only conclusion I follows.

     

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