Logical Reasoning & DI (LRDI) Test - 8

Let’s start with the information provided in (ii). We know that each country won a different number of gold, silver and bronze medals and no two countries have the same number of medals in a single category. Since the number of events are 15, the number of gold, silver, and bronze medals a country could have won can be 0,1,2,3,4, and 5. Now, Australia won 5 gold medals (by iv). Also England and China have the maximum number of medals. This is only possible when they have 3, 4, and 5 medals in the three categories in no particular order. Since, Australia has 5 gold medals and England has more gold medals than China, China must have 3 and England must have 4 gold medals. Also, by (iii) we can infer that England has 3 bronze medals. Thus, England must have 5 silver medals. From this we can infer that China has 4 silver and 5 bronze medals. India and China have least number of medals. So, they must have (0,1, and 2) medals in no particular order. But, by (v) we can infer that India has 1 gold medal leaving 0 for Pakistan. This means India has 0 silver and 2 bronze medals and Pakistan has 2 silver and 1 bronze medal. The rest of the table can be completed as follows-

We can see that China, Australia, and England, all won more than 8 medals.

Let’s start with the information provided in (ii). We know that each country won a different number of gold, silver and bronze medals and no two countries have the same number of medals in a single category. Since the number of events are 15, the number of gold, silver, and bronze medals a country could have won can be 0,1,2,3,4, and 5. Now, Australia won 5 gold medals (by iv). Also England and China have the maximum number of medals. This is only possible when they have 3, 4, and 5 medals in the three categories in no particular order. Since, Australia has 5 gold medals and England has more gold medals than China, China must have 3 and England must have 4 gold medals. Also, by (iii) we can infer that England has 3 bronze medals. Thus, England must have 5 silver medals. From this we can infer that China has 4 silver and 5 bronze medals. India and China have least number of medals. So, they must have (0,1, and 2) medals in no particular order. But, by (v) we can infer that India has 1 gold medal leaving 0 for Pakistan. This means India has 0 silver and 2 bronze medals and Pakistan has 2 silver and 1 bronze medal. The rest of the table can be completed as follows-

We can see that Pakistan won the least number of gold medals.

Let’s start with the information provided in (ii). We know that each country won a different number of gold, silver and bronze medals and no two countries have the same number of medals in a single category. Since the number of events are 15, the number of gold, silver, and bronze medals a country could have won can be 0,1,2,3,4, and 5. Now, Australia won 5 gold medals (by iv). Also England and China have the maximum number of medals. This is only possible when they have 3, 4, and 5 medals in the three categories in no particular order. Since, Australia has 5 gold medals and England has more gold medals than China, China must have 3 and England must have 4 gold medals. Also, by (iii) we can infer that England has 3 bronze medals. Thus, England must have 5 silver medals. From this we can infer that China has 4 silver and 5 bronze medals. India and China have least number of medals. So, they must have (0,1, and 2) medals in no particular order. But, by (v) we can infer that India has 1 gold medal leaving 0 for Pakistan. This means India has 0 silver and 2 bronze medals and Pakistan has 2 silver and 1 bronze medal. The rest of the table can be completed as follows-

We can see that 4 countries won more silver medal than gold medals.

Let’s start with the information provided in (ii). We know that each country won a different number of gold, silver and bronze medals and no two countries have the same number of medals in a single category. Since the number of events are 15, the number of gold, silver, and bronze medals a country could have won can be 0,1,2,3,4, and 5. Now, Australia won 5 gold medals (by iv). Also England and China have the maximum number of medals. This is only possible when they have 3, 4, and 5 medals in the three categories in no particular order. Since, Australia has 5 gold medals and England has more gold medals than China, China must have 3 and England must have 4 gold medals. Also, by (iii) we can infer that England has 3 bronze medals. Thus, England must have 5 silver medals. From this we can infer that China has 4 silver and 5 bronze medals. India and China have least number of medals. So, they must have (0,1, and 2) medals in no particular order. But, by (v) we can infer that India has 1 gold medal leaving 0 for Pakistan. This means India has 0 silver and 2 bronze medals and Pakistan has 2 silver and 1 bronze medal. The rest of the table can be completed as follows-

We can see that China won the most number of Gold medals.

Let’s start with the information provided in (ii). We know that each country won a different number of gold, silver and bronze medals and no two countries have the same number of medals in a single category. Since the number of events are 15, the number of gold, silver, and bronze medals a country could have won can be 0,1,2,3,4, and 5. Now, Australia won 5 gold medals (by iv). Also England and China have the maximum number of medals. This is only possible when they have 3, 4, and 5 medals in the three categories in no particular order. Since, Australia has 5 gold medals and England has more gold medals than China, China must have 3 and England must have 4 gold medals. Also, by (iii) we can infer that England has 3 bronze medals. Thus, England must have 5 silver medals. From this we can infer that China has 4 silver and 5 bronze medals. India and China have least number of medals. So, they must have (0,1, and 2) medals in no particular order. But, by (v) we can infer that India has 1 gold medal leaving 0 for Pakistan. This means India has 0 silver and 2 bronze medals and Pakistan has 2 silver and 1 bronze medal. The rest of the table can be completed as follows-

Only India and Pakistan won less than 5 medals in total.

Since Idea charges Rs 1400 per GB, Jio and Voda must charge Rs 1000 and Rs 600 respectively. Now, there will be 2 cases, first where Airtel charges Rs 500 and second where BSNL charges Rs 500.
Case 1:

Since everybody paid a bill more than Rs 20000, A must have used either 50 or 60 GB and E must have used one of 40/50/60 GBs.
If A uses 60 GB, then even if E uses 50 GB, A’s bill won’t be greater than that of E’s. Thus, A must have used 50 GB and E 40 GB. Now, C can’t use 25 GB and B can’t use 25 GB because then its bill will be equal to A. Thus, D uses 25 GB. But, now D’s bill will be Rs 30000 which is not possible. Thus, this case is not possible.

Case 2:
In this case, Airtel charges Rs 1200/GB. Since everybody paid more than Rs 20000, D must have used either 50 GB or 60 GB and E must have used one among 40/50/60 GB. But D can’t use 60 since in that case its bill will be Rs 30000 which is not possible. So, D uses 50 GB. Now, A has to use 25 GB since C doesn’t use 25 GB and B can’t use 25 GB since D’s bill is 25 k. Now A(bill) > E(bill). Thus, among 40/60 GB, E must use 40 GB. Now, B can’t use 30 since A’s bill is 30k. So B uses 60 GB and C use 30 GB.
The following table represents the final arrangement.

From the final table, we can notice that B pays the highest amount.

Since Idea charges Rs 1400 per GB, Jio and Voda must charge Rs 1000 and Rs 600 respectively. Now, there will be 2 cases, first where Airtel charges Rs 500 and second where BSNL charges Rs 500.
Case 1:

Since everybody paid a bill more than Rs 20000, A must have used either 50 or 60 GB and E must have used one of 40/50/60 GBs.
If A uses 60 GB, then even if E uses 50 GB, A’s bill won’t be greater than that of E’s. Thus, A must have used 50 GB and E 60 GB. Now, C can’t use 25 GB and B can’t use 25 GB because then its bill will be equal to A. Thus, D uses 25 GB. But, now D’s bill will be Rs 30000 which is not possible. Thus, this case is not possible.

Case 2:
In this case, Airtel charges Rs 1200/GB. Since everybody paid more than Rs 20000, D must have used either 50 GB or 60 GB and E must have used one among 40/50/60 GB. But D can’t use 60 since in that case its bill will be Rs 30000 which is not possible. So, D uses 50 GB. Now, A has to use 25 GB since C doesn’t use 25 GB and B can’t use 25 GB since D’s bill is 25 k. Now A(bill) > E(bill). Thus, among 40/60 GB, E must use 40 GB. Now, B can’t use 30 since A’s bill is 30k. So B uses 60 GB and C use 30 GB.
The following table represents the final arrangement.

If BSNL increases the charge by 140%, the new charge will be 500 X 2.4 = Rs 1200. Then the bill paid by D will be Rs 60000 which will be the same as B. Thus the answer is D.

Since Idea charges Rs 1400 per GB, Jio and Voda must charge Rs 1000 and Rs 600 respectively. Now, there will be 2 cases, first where Airtel charges Rs 500 and second where BSNL charges Rs 500.
Case 1:

Since everybody paid a bill more than Rs 20000, A must have used either 50 or 60 GB and E must have used one of 40/50/60 GBs.
If A uses 60 GB, then even if E uses 50 GB, A’s bill won’t be greater than that of E’s. Thus, A must have used 50 GB and E 60 GB. Now, C can’t use 25 GB and B can’t use 25 GB because then its bill will be equal to A. Thus, D uses 25 GB. But, now D’s bill will be Rs 30000 which is not possible. Thus, this case is not possible.

Case 2:
In this case, Airtel charges Rs 1200/GB. Since everybody paid more than Rs 20000, D must have used either 50 GB or 60 GB and E must have used one among 40/50/60 GB. But D can’t use 60 since in that case its bill will be Rs 30000 which is not possible. So, D uses 50 GB. Now, A has to use 25 GB since C doesn’t use 25 GB and B can’t use 25 GB since D’s bill is 25 k. Now A(bill) > E(bill). Thus, among 40/60 GB, E must use 40 GB. Now, B can’t use 30 since A’s bill is 30k. So B uses 60 GB and C uses 30 GB.
The following table represents the final arrangement.

Airtel gives 250 MB free on the usage of 1 GB. This means that subscribers are getting 25% more for the same price. Thus, A who needs 25 GB would only have to buy 20 GB data. Thus, the bill he would pay is 20 X 1200 = Rs 24000

Since Idea charges Rs 1400 per GB, Jio and Voda must charge Rs 1000 and Rs 600 respectively. Now, there will be 2 cases, first where Airtel charges Rs 500 and second where BSNL charges Rs 500.
Case 1:
Since everybody paid a bill more than Rs 20000, A must have used either 50 or 60 GB and E must have used one of 40/50/60 GBs.
If A uses 60 GB, then even if E uses 50 GB, A’s bill won’t be greater than that of E’s. Thus, A must have used 50 GB and E 60 GB. Now, C can’t use 25 GB and B can’t use 25 GB because then its bill will be equal to A. Thus, D uses 25 GB. But, now D’s bill will be Rs 30000 which is not possible. Thus, this case is not possible.

Case 2:
In this case, Airtel charges Rs 1200/GB. Since everybody paid more than Rs 20000, D must have used either 50 GB or 60 GB and E must have used one among 40/50/60 GB. But D can’t use 60 since in that case its bill will be Rs 30000 which is not possible. So, D uses 50 GB. Now, A has to use 25 GB since C doesn’t use 25 GB and B can’t use 25 GB since D’s bill is 25 k. Now A(bill) > E(bill). Thus, among 40/60 GB, E must use 40 GB. Now, B can’t use 30 since A’s bill is 30k. So B uses 60 GB and C uses 30 GB.
The following table represents the final arrangement.

Airtel gives 200 MB free on the usage of 1 GB. This means that subscribers are getting 25% more for the same price. Thus, A who needs 25 GB would only have to buy 20 GB data. Thus, the bill he would pay is 20 X 1200 = Rs 24000. This is joint lowest with E. Thus, the difference is 0.

Since Idea charges Rs 1400 per GB, Jio and Voda must charge Rs 1000 and Rs 600 respectively. Now, there will be 2 cases, first where Airtel charges Rs 500 and second where BSNL charges Rs 500.
Case 1:
Since everybody paid a bill more than Rs 20000, A must have used either 50 or 60 GB and E must have used one of 40/50/60 GBs.
If A uses 60 GB, then even if E uses 50 GB, A’s bill won’t be greater than that of E’s. Thus, A must have used 50 GB and E 60 GB. Now, C can’t use 25 GB and B can’t use 25 GB because then its bill will be equal to A. Thus, D uses 25 GB. But, now D’s bill will be Rs 30000 which is not possible. Thus, this case is not possible.

Case 2:
In this case, Airtel charges Rs 1200/GB. Since everybody paid more than Rs 20000, D must have used either 50 GB or 60 GB and E must have used one among 40/50/60 GB. But D can’t use 60 since in that case its bill will be Rs 30000 which is not possible. So, D uses 50 GB. Now, A has to use 25 GB since C doesn’t use 25 GB and B can’t use 25 GB since D’s bill is 25 k. Now A(bill) > E(bill). Thus, among 40/60 GB, E must use 40 GB. Now, B can’t use 30 since A’s bill is 30k. So B uses 60 GB and C uses 30 GB.
The following table represents the final arrangement.

Amount paid by B is 60k. Amount paid by E is 60k if charge per GB is 1500.

Required% = $$\ \frac{1500-600}{600}\times100$$ = 150%

The answer is option C.

Stage A and Stage D do not have any prerequisite stages. Thus, the company will start with the following two stages. As soon stage D is completed stage F will continue as the only prerequisite stage of F is stage D.

While on the other hand, when stage A will complete stage H will start, as it has only stage A as a prerequisite.

As soon as F and H will finish G will start as it is the only stage which can proceed after the completion of stages A, D, F and H

The following table gives the minimum number of weeks after which a particular stage can be started

From the table, we can see that all the stages can be completed in 7 weeks.

Stage A and Stage D do not have any prerequisite stages. Thus, the company will start with the following two stages. As soon stage D is completed stage F will continue as the only prerequisite stage of F is stage D.

While on the other hand, when stage A will complete stage H will start, as it has only stage A as a prerequisite.

As soon as F and H will finish G will start as it is the only stage which can proceed after the completion of stages A, D, F and H

The following table gives the minimum number of weeks after which a particular stage can be started

From the table, we can see that under normal circumstances G would be completed in 5 weeks. Since G can only be started after 6 weeks, G would be completed on the seventh week. The stages directly or indirectly dependent on G is E,B and C. revised E and C can be completed after one week of G's completion but B can be completed only after two weeks from G's completion.
Thus, the minimum time required to complete a new application is 7 + 2 = 9 weeks.

There are two different ways in which the process can be completed in minimum weeks. They are:

or

In both the cases, the overlap between two stages occurs in 5 weeks.

From the table, we can see that if the development is completed in minimum time, there would be overlap between different stages in 5 weeks.

The following table gives the minimum number of weeks after which a particular stage can be started

From the table, we can see that if D is independent of any other stages, the minimum number of days required for completion of all the stages development on D is 7 weeks. But this also involves a 1 week delay due to the dependency on H for beginning D. Thus, if D was dependent on H, all stages dependent on D would be completed in 6 weeks. Stage H requires at least 4 weeks for completion. Thus, the minimum number of weeks required if D is dependent on H is 6 + 4 = 10 weeks.

The following table gives the minimum number of weeks after which a particular stage can be started

From the table, we can see that if D is independent of any other stages, the minimum number of days required for completion of all the stages development on D is 7 weeks. But this also involves a 1 week delay due to the dependency on H for beginning D. Thus, if D was dependent on H, all stages dependent on D would be completed in 6 weeks. Stage H requires at least 4 weeks for completion. Thus, the minimum number of weeks required if D is dependent on H is 6 + 4 = 10 weeks.

The overlap between two stages occurs in 2 weeks, i.e. 9th and 10th.

The answer is option C.

Sachin scored one-ninth of his total runs in the first match, one-fifth of his total runs in the second match, one-sixth of his total runs in the third match and one-eleventh of his total runs in his fourth match.
=> Minimum number of runs scored by Sachin = LCM(9, 5, 6, 11) = 990 => Runs scored by Sachin = 990a
Sehwag scored one-twelveth of his total runs in the first match, one-seventh of his total runs in the second match, one-eighth of his total runs in the third match and one-fourth of his total runs in his fourth match.
=> Minimum number of runs scored by Sehwag = LCM(12, 7, 8, 4) = 168 => Runs scored by Sehwag = 168b
Kohli scored one-thirteenth of his total runs in the first match, one-sixth of his total runs in the second match, one-third of his total runs in the third match and one-sixteen of his total runs in his fourth match.
=> Minimum number of runs scored by Kohli = LCM(13, 6, 3, 16) = 624 => Runs scored by Kohli = 624c
Dhoni scored one-fourth of his total runs in the first match, one-fifth of his total runs in the second match, one-sixth of his total runs in the third match and one-seventh of his total runs in his fourth match.
=> Minimum number of runs scored by Dhoni = LCM(4, 5, 6, 7) = 420 => Runs scored by Dhoni = 420d
Ganguly scored one-third of his total runs in the first match, one-tenth of his total runs in the second match, one-fifth of his total runs in the third match and one-ninth of his total runs in his fourth match.
=> Minimum number of runs scored by Ganguly = LCM(3, 10, 5, 9) = 90 => Runs scored by Ganguly = 90e
Minimum number of runs scored by 5 batsman = 990 + 168 + 624 + 420 + 90 = 2292
Maximum possible runs are 2460 => Difference = 2460 - 2292 = 168
=> It is possible that either Sehwag scored 336 runs or Ganguly scored 180 runs. Sachin, Kohli and Dhoni scored 990, 624 and 420 runs respectively.
=> Sachin scored the highest number of runs.

Sachin scored one-ninth of his total runs in the first match, one-fifth of his total runs in the second match, one-sixth of his total runs in the third match and one-eleventh of his total runs in his fourth match.
=> Minimum number of runs scored by Sachin = LCM(9, 5, 6, 11) = 990 => Runs scored by Sachin = 990a
Sehwag scored one-twelveth of his total runs in the first match, one-seventh of his total runs in the second match, one-eighth of his total runs in the third match and one-fourth of his total runs in his fourth match.
=> Minimum number of runs scored by Sehwag = LCM(12, 7, 8, 4) = 168 => Runs scored by Sehwag = 168b
Kohli scored one-thirteenth of his total runs in the first match, one-sixth of his total runs in the second match, one-third of his total runs in the third match and one-sixteen of his total runs in his fourth match.
=> Minimum number of runs scored by Kohli = LCM(13, 6, 3, 16) = 624 => Runs scored by Kohli = 624c
Dhoni scored one-fourth of his total runs in the first match, one-fifth of his total runs in the second match, one-sixth of his total runs in the third match and one-seventh of his total runs in his fourth match.
=> Minimum number of runs scored by Dhoni = LCM(4, 5, 6, 7) = 420 => Runs scored by Dhoni = 420d
Ganguly scored one-third of his total runs in the first match, one-tenth of his total runs in the second match, one-fifth of his total runs in the third match and one-ninth of his total runs in his fourth match.
=> Minimum number of runs scored by Ganguly = LCM(3, 10, 5, 9) = 90 => Runs scored by Ganguly = 90e
Minimum number of runs scored by 5 batsman = 990 + 168 + 624 + 420 + 90 = 2292
Maximum possible runs are 2460 => Difference = 2460 - 2292 = 168
=> It is possible that either Sehwag scored 336 runs or Ganguly scored 180 runs. Sachin, Kohli and Dhoni scored 990, 624 and 420 runs respectively.
Sachin's score in fourth match = 990/11 = 90
Sehwag's score in fourth match can be either 168/4, which is equal to 42, or 336/4, which is equal to 84.
Kohli's score in fourth match = 624/16 = 39
Dhoni's score in fourth match = 420/7 = 60
Ganguly's score in fourth match can be either 90/9, which is equal to 10, or 180/9, which is equal to 20.
So, second highest run scorer can be either Dhoni or Sehwag => Cannot be determined.

Sachin scored one-ninth of his total runs in the first match, one-fifth of his total runs in the second match, one-sixth of his total runs in the third match and one-eleventh of his total runs in his fourth match.
=> Minimum number of runs scored by Sachin = LCM(9, 5, 6, 11) = 990 => Runs scored by Sachin = 990a
Sehwag scored one-twelveth of his total runs in the first match, one-seventh of his total runs in the second match, one-eighth of his total runs in the third match and one-fourth of his total runs in his fourth match.
=> Minimum number of runs scored by Sehwag = LCM(12, 7, 8, 4) = 168 => Runs scored by Sehwag = 168b
Kohli scored one-thirteenth of his total runs in the first match, one-sixth of his total runs in the second match, one-third of his total runs in the third match and one-sixteen of his total runs in his fourth match.
=> Minimum number of runs scored by Kohli = LCM(13, 6, 3, 16) = 624 => Runs scored by Kohli = 624c
Dhoni scored one-fourth of his total runs in the first match, one-fifth of his total runs in the second match, one-sixth of his total runs in the third match and one-seventh of his total runs in his fourth match.
=> Minimum number of runs scored by Dhoni = LCM(4, 5, 6, 7) = 420 => Runs scored by Dhoni = 420d
Ganguly scored one-third of his total runs in the first match, one-tenth of his total runs in the second match, one-fifth of his total runs in the third match and one-ninth of his total runs in his fourth match.
=> Minimum number of runs scored by Ganguly = LCM(3, 10, 5, 9) = 90 => Runs scored by Ganguly = 90e
Minimum number of runs scored by 5 batsman = 990 + 168 + 624 + 420 + 90 = 2292
Maximum possible runs are 2460 => Difference = 2460 - 2292 = 168
=> It is possible that either Sehwag scored 336 runs or Ganguly scored 180 runs. Sachin, Kohli and Dhoni scored 990, 624 and 420 runs respectively.
Runs scored in match 1 => 990/9 + (168 or 336)/12 + 624/13 + 420/4 + (90 or 180)/3 = 110 + (14 or 28) + 48 + 105 + (30 or 60) => Possible scores are 307, 321 and 337
Runs scored in match 2 => 990/5 + (168 or 336)/7 + 624/6 + 420/5 + (90 or 180)/10 = 198 + (24 or 48) + 104 + 84 + (9 or 18) => Possible scores are 419, 428 and 443
Runs scored in match 3 => 990/6 + (168 or 336)/8 + 624/3 + 420/6 + (90 or 180)/5 = 165 + (21 or 42) + 208 + 70 + (18 or 36) => Possible scores are 482, 500 and 503
Runs scored in match 4 => 990/11 + (168 or 336)/4 + 624/16 + 420/7 + (90 or 180)/9 = 90 + (42 or 84) + 39 + 60 + (10 or 20) => Possible scores are 241, 251 and 283
The maximum possible runs scored by these players in the four matches = 337 + 443 + 503 + 283 = 1566
So, at least 2292 - 1566 = 726 runs were scored in match 5 => Highest number of runs are scored in match 5.

Sachin scored one-ninth of his total runs in the first match, one-fifth of his total runs in the second match, one-sixth of his total runs in the third match and one-eleventh of his total runs in his fourth match.
=> Minimum number of runs scored by Sachin = LCM(9, 5, 6, 11) = 990 => Runs scored by Sachin = 990a
Sehwag scored one-twelveth of his total runs in the first match, one-seventh of his total runs in the second match, one-eighth of his total runs in the third match and one-fourth of his total runs in his fourth match.
=> Minimum number of runs scored by Sehwag = LCM(12, 7, 8, 4) = 168 => Runs scored by Sehwag = 168b
Kohli scored one-thirteenth of his total runs in the first match, one-sixth of his total runs in the second match, one-third of his total runs in the third match and one-sixteen of his total runs in his fourth match.
=> Minimum number of runs scored by Kohli = LCM(13, 6, 3, 16) = 624 => Runs scored by Kohli = 624c
Dhoni scored one-fourth of his total runs in the first match, one-fifth of his total runs in the second match, one-sixth of his total runs in the third match and one-seventh of his total runs in his fourth match.
=> Minimum number of runs scored by Dhoni = LCM(4, 5, 6, 7) = 420 => Runs scored by Dhoni = 420d
Ganguly scored one-third of his total runs in the first match, one-tenth of his total runs in the second match, one-fifth of his total runs in the third match and one-ninth of his total runs in his fourth match.
=> Minimum number of runs scored by Ganguly = LCM(3, 10, 5, 9) = 90 => Runs scored by Ganguly = 90e
Minimum number of runs scored by 5 batsman = 990 + 168 + 624 + 420 + 90 = 2292
Maximum possible runs are 2460 => Difference = 2460 - 2292 = 168
=> It is possible that either Sehwag scored 336 runs or Ganguly scored 180 runs. Sachin, Kohli and Dhoni scored 990, 624 and 420 runs respectively.
Runs scored in match 1 by Sachin, Sehwag, Kohli, Dhoni and Ganguly => 110, (14 or 28), 48, 105, (30 or 60)
Runs scored in match 2 by Sachin, Sehwag, Kohli, Dhoni and Ganguly => 198, (24 or 48), 104, 84, (9 or 18)
Runs scored in match 3 by Sachin, Sehwag, Kohli, Dhoni and Ganguly => 165, (21 or 42), 208, 70, (18 or 36)
Runs scored in match 4 by Sachin, Sehwag, Kohli, Dhoni and Ganguly => 90, (42 or 84), 39, 60, (10 or 20)
Sachin's score in match 5 = 990 - 110 - 198 - 165 - 90 = 427, which is the highest score in a match by a batsman and he scored it in Match 5.

Sachin scored one-ninth of his total runs in the first match, one-fifth of his total runs in the second match, one-sixth of his total runs in the third match and one-eleventh of his total runs in his fourth match.
=> Minimum number of runs scored by Sachin = LCM(9, 5, 6, 11) = 990 => Runs scored by Sachin = 990a
Sehwag scored one-twelveth of his total runs in the first match, one-seventh of his total runs in the second match, one-eighth of his total runs in the third match and one-fourth of his total runs in his fourth match.
=> Minimum number of runs scored by Sehwag = LCM(12, 7, 8, 4) = 168 => Runs scored by Sehwag = 168b
Kohli scored one-thirteenth of his total runs in the first match, one-sixth of his total runs in the second match, one-third of his total runs in the third match and one-sixteen of his total runs in his fourth match.
=> Minimum number of runs scored by Kohli = LCM(13, 6, 3, 16) = 624 => Runs scored by Kohli = 624c
Dhoni scored one-fourth of his total runs in the first match, one-fifth of his total runs in the second match, one-sixth of his total runs in the third match and one-seventh of his total runs in his fourth match.
=> Minimum number of runs scored by Dhoni = LCM(4, 5, 6, 7) = 420 => Runs scored by Dhoni = 420d
Ganguly scored one-third of his total runs in the first match, one-tenth of his total runs in the second match, one-fifth of his total runs in the third match and one-ninth of his total runs in his fourth match.
=> Minimum number of runs scored by Ganguly = LCM(3, 10, 5, 9) = 90 => Runs scored by Ganguly = 90e
Minimum number of runs scored by 5 batsman = 990 + 168 + 624 + 420 + 90 = 2292
Maximum possible runs are 2460 => Difference = 2460 - 2292 = 168
=> It is possible that either Sehwag scored 336 runs or Ganguly scored 180 runs. Sachin, Kohli and Dhoni scored 990, 624 and 420 runs respectively.
Maximum runs in Match 5 is possible when total runs score by all of them in 5 matches is maximum, i.e. when Sehwag scored 336 runs.
Runs scored in Match 5 by all players = 427 + 134 + 225 + 101 + 23 = 910
The answer is 910.