Constructions Test

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Constructions Test - 7

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Weekly Quiz Competition

Question 1
1 / -0

In division of a line segment AB, any ray AX making angle with AB is:

A
Acute angle

B
Right angle

C
Obtuse angle

D
Any arbitrary angle

Solution

In division of a line segment AB, any ray AX making angle with AB is an acute angle always because of path of ray.
Question 2
1 / -0

Which theorem criterion we are using in giving the justification of the division of a line segment by usual method ?

A
Area theorem

B
Pythagoras theorem

C
SSS criterion

D
Basic Proportionality theorem

Solution

The intercept theorem, also known as Thales' theorem or basic proportionality theorem, is an important theorem in elementary geometry about the ratios of various line segments that are created if two intersecting lines are intercepted by a pair of parallels. It is equivalent to the theorem about ratios in similar triangles.
Question 3
1 / -0

To divide a line segment AB in the ratio 5: 7, first a ray AX is drawn so that ∠BAX is an acute angle and then at equal distances points are marked on the ray AX such that the minimum number of these points is

A
11

B
12

C
8

D
10

Solution

According to the question, the minimum number of those points which are to be marked should be (Numerator + Denominator) i.e., 5 + 7 = 12
Question 4
1 / -0

To divide a line segment AB in the ration 4 : 7, a ray AX is drawn first such that ∠BAX is an acute angle and then points A₁,A₂,A₃,…. are located at equal distances on the ray AX and the point B is joined to

A
A₉

B
A₁₀

C
A₁₁

D
A₁₂

Solution

To divide a line segment AB in the ratio m:n (when m > n), a ray AX is drawn such that ∠BAX is an acute angle and then points A₁,A₂,A₃...A_m,…..A_n…. are located at equal distances on the ray AX and then the point B is joined to A_n
Therefore, according to the question, the point is B joined to A₁₁.
Question 5
1 / -0

To divide line segment AB in the ratio a:b ( a, b are positive integers), draw a ray AX so that ∠BAX is an acute angle and then mark points on ray AX at equal distances such that the minimum number of these points is

A
( a + b)

B
Greater of a and b

C
ab

D
(a + b – 1)

Solution

According to the question, the minimum number of those points which are to be marked should be (Numerator + Denominator) i.e., (a + b)
Question 6
1 / -0

To divide a line segment AB in the ratio 2 : 3, first a ray AX is drawn so that ∠BAX is an acute angle and then at equal distances, points are marked on the ray AX, such that the minimum number of these points is

A
2

B
3

C
5

D
6

Solution

According to the question, the minimum number of those points which are to be marked should be (Numerator + Denominator) i.e., 2 + 3 = 5

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Constructions Test - 7

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Constructions Test - 7

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SHARING IS CARING

Question 1

Acute angle

Right angle

Obtuse angle

Any arbitrary angle

Solution

Question 2

Area theorem

Pythagoras theorem

SSS criterion

Basic Proportionality theorem

Solution

Question 3

11

12

8

10

Solution

Question 4

A9

A10

A11

A12

Solution

Question 5

( a + b)

Greater of a and b

ab

(a + b – 1)

Solution

Question 6

2

3

5

6

Solution

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A₉

A₁₀

A₁₁

A₁₂