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Probability Test - 7

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Probability Test - 7
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  • Question 1
    1 / -0

    If ‘p’ is the probability of an event, then p satisfies

    Solution

    Probability of an event always lie between 0 and 1

  • Question 2
    1 / -0

    A bag contains 5 black balls, 4 white balls and 3 red balls. If a ball is selected at random, the probability that it is not red is

    Solution

    Numbers of balls which are not red = 12 – 3 = 9
    Number of possible outcomes = 9
    Number of Total outcomes = 12
    Required Probability = 9/12=3/4

  • Question 3
    1 / -0

    Two dice are thrown simultaneously. The probability of getting a doublet is

    Solution

    Doublet means getting same number on both dice simultaneously 
    Doublets = (1, 1), (2, 2), (3, 3), (4, 4), (5, 5), (6, 6)
    Number of possible outcomes = 6
    Total number of ways to throw a dice = 36
    Probability of getting a doublet = 6/36=1/6

  • Question 4
    1 / -0

    An unbiased die is thrown once. The probability of getting a prime or composite number is

    Solution

    prime numbers on a die are  2 , 3, 5
    composite numbers on a die are 4 , 6
    Prime and Composite numbers on a die = 2, 3, 4, 5, 6
    Number of possible outcomes = 5
    Number of Total outcomes = 6
    Required Probability =5/6

  • Question 5
    1 / -0

    The probability of getting 3 head or 3 tails in tossing a coin 3 times is

    Solution

    Total outcomes = {HHH, HHT, HTH, HTT, THH, THT, TTH, TTT) = 8
    Number of possible outcomes = (HHH) or (TTT) = 2
    Required Probability = 2/8=1/4

  • Question 6
    1 / -0

    The probability that a leap year will have 53 Sundays or 53 Mondays is

    Solution

    Leap year contains 366 days = 52 weeks + 2 days
    52 weeks contain 52 Sundays and 52 weeks contain 52 Mondays
    We will get 53 Sundays or 53 Mondays if one of the remaining two days is a Sunday or Monday Total possibilities for two days are:
    (Sunday, Monday), (Monday, Tuesday), (Tuesday, Wednesday), (Wednesday, Thursday), (Thursday, Friday), (Friday, Saturday), (Saturday, Sunday)
    Number of Total possible outcomes = 7
    Number of possible outcomes either Sunday or Monday or Both = 3
    Required Probability = 3/7

  • Question 7
    1 / -0

    The probability that a non leap year will have 53 Fridays and 53 Saturdays is

    Solution

    Non-leap year contains 366 days = 52 weeks + 1 day
    52 weeks contain 52 Fridays and 52 weeks contain 52 Saturdays
    We will get 53 Fridays or 53 Saturdays if remaining one day is a Friday and Saturday
    Therefore, Total possibility is zero.
    Number of Total possible outcomes = 7
    Number of possible outcomes Friday and Saturday = 0
    Required Probability = 0/7=0

  • Question 8
    1 / -0

    The probability of selecting a queen of diamonds when a card is drawn from well shuffled pack of 52 cards is

    Solution

    Number of possible outcomes (queen of diamonds) = 1
    Number of Total outcomes = 52
    Required Probability = 1/52

  • Question 9
    1 / -0

    A card is drawn from a pack of 52 cards at random. The probability of getting neither an ace nor a king card is

    Solution

    Number of Total outcomes = 52
    Number of aces and Number of kings = 4 + 4 = 8
    Number of cards except ace and king = 52 – 8 = 44
    Required Probability = 44/52=11/13

  • Question 10
    1 / -0

    A card is drawn from a pack of 52 cards at random. The probability of getting either an ace or a king card is

    Solution

    Number of Total outcomes = 52
    Number of aces and Number of kings = 4 + 4 = 8
    Required Probability = 8/52=2/13

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