Quadratic Equations Test

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Quadratic Equations Test - 5

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Weekly Quiz Competition

Question 1
1 / -0

If 1/2 is a root of the equation x² + kx – 5/4=0, then the value of k is

A
1/2

B
2

C
-2

D
1/4
Question 2
1 / -0

If the list price of a toy is reduced by 2, a person can buy 2 toys more for 360. The original price of the toy is

A
18

B
20

C
19

D
21
Question 3
1 / -0

If the equation x² – kx +9 = 0 does not possess real roots, then

A
– 6 < k < 6

B
k > 6

C
k < – 6

D
k = ± 6
Question 4
1 / -0

Which of the following is a quadratic equation?

A
(4–x) (3x+1) = 2–3x²

B
(x+3)² – 5 = x2 + 9

C
(k–4)x²– 3x = 9k – 4 (k = 4)

D
(x + 1)³ = x³ – 5
Question 5
1 / -0

Which of the following equations has – 1 as a root?

A
x² + 3x – 10 = 0

B
x² – x – 12 = 0

C
3x² – 2x – 5 = 0

D
9x² + 24x + 16 = 0
Question 6
1 / -0

If the difference of roots of the quadratic equation x2 + kx + 12 = 0 is 1, the positive value of k is

A
-7

B
7

C
4

D
8

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Re-Attempt Weekly Quiz Competition

Quadratic Equations Test - 5

Result

Quadratic Equations Test - 5

Score

-

Rank

-

SHARING IS CARING

Question 1

1/2

2

-2

1/4

Question 2

18

20

19

21

Question 3

– 6 < k < 6

k > 6

k < – 6

k = ± 6

Question 4

(4–x) (3x+1) = 2–3x2

(x+3)2 – 5 = x2 + 9

(k–4)x2 – 3x = 9k – 4 (k = 4)

(x + 1)3 = x3 – 5

Question 5

x2 + 3x – 10 = 0

x2 – x – 12 = 0

3x2 – 2x – 5 = 0

9x2 + 24x + 16 = 0

Question 6

-7

7

4

8

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(4–x) (3x+1) = 2–3x²

(x+3)² – 5 = x2 + 9

(k–4)x²– 3x = 9k – 4 (k = 4)

(x + 1)³ = x³ – 5

x² + 3x – 10 = 0

x² – x – 12 = 0

3x² – 2x – 5 = 0

9x² + 24x + 16 = 0