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Arithmetic Progressions Test -10

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Arithmetic Progressions Test -10
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  • Question 1
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    The 17th term of an AP exceeds its 10th term by 7, then the common difference is

    Solution

    According to question,
    Given that the 17th term of an A.P exceeds its 10th term by 7 . 
    d = ?
    ⇒a+16d = a+9d+7
    ⇒16d-9d = 7
    ⇒7d = 7
    ⇒d = 7/7 = 1 .
    Therefore , common difference = 1.

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