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Arithmetic Progressions Test -11

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Arithmetic Progressions Test -11
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    The nth term of the A.P. 63, 65, 67, 69, ……..and the A.P. 3, 10, 17, 24, …….. are equal, then the value of ‘n’ is

    Solution

    For 1st  A.P. ; a = 63 and d = 2 , hence Tn = 63 + (n - 1)2 

    ⇒ Tn = 2n + 61 - - - - - - - (i) 

    for 2nd AP   a = 3 ,  d=7 ,  hence tn = 3 + (n- 1)7

    tn = 7n - 4 ........................ ii

    by condition, from (i) & (ii), 7n - 4 = 2n + 61 

    ⇒ 5n = 65 
    ∴n = 13

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