Triangles Test ...

If $$\triangle ABC\sim \triangle  PQR,$$  $$ \cfrac{ar(ABC)}{ar(PQR)}=\cfrac{9}{4}$$,  $$AB=18$$ $$cm$$ and $$BC=15$$ $$cm$$, then $$QR$$ is equal to:

It is given that $$\triangle ABC \sim \triangle PQR$$, $$A(\triangle ABC)=36{cm}^{2}$$ and $$A(\triangle PQR)=25{cm}^{2}$$. If $$QR=6$$cm, find the length of $$BC$$.

$$\triangle ABC$$ and $$\triangle BDE$$ are two equilateral triangles such that $$D$$ is the midpoint of $$BC$$. Ratio of $$A(\triangle ABC)$$ and $$A(\triangle BDE)$$ is:

Let $$\triangle ABC\sim \triangle DEF$$ and their areas be, respectively $$64\ {cm}^{2}$$ and $$121\ {cm}^{2}$$. If $$EF=15.4\ cm$$, find $$BC$$.

In figure, $$DE\parallel BC$$. Find the length of $$EC$$.

In the diagram given below, $$\displaystyle \angle ABD=\angle CDB=\angle PQD=90^{\circ}.$$  If $$ AB:CD=3:1,$$ the ratio of CD : PQ is 

In $$\displaystyle \Delta ABC, PQ\parallel BC$$ and area of quadrilateral $$PBCQ = 42\ sq. cm$$. If $$AP : PB = 2 : 3,$$ then find the area of $$\displaystyle \Delta APQ$$.

The corresponding sides of two similar triangles are in the ratio $$2$$ : $$3$$. If the area of the smaller triangle is $$12$$ the area of the larger is

In a $$\displaystyle \Delta ABC$$, $$D$$ is any point on $$AB$$ and $$DE || BC $$ meets $$AC$$ at E if $$AD = 2.5, DB = 6$$ cm and $$AE = 3$$ cm, then $$EC = $$

If $$\triangle ABC$$ is right angled at $$B$$ and $$M,$$ $$N$$ are the midpoints of $$AB$$ and $$BC$$ respectively, then $$4\left ( AN^{2}+CM^{2} \right )=$$