Coordinate Geom...

$$A(5,1)$$, $$B(1,5)$$ and $$C(-3, -1)$$ are the vertices of $$\Delta ABC$$. The length of its median AD is:

The coordinates of the centre of a circle are $$(-6,1.5)$$. If the ends of a diameter are $$(-3,y)$$ and $$(x, -2)$$ then:

Consider the points $$A( a, b + c)$$, $$B(b, c + a)$$, and $$C(c, a +b)$$ be the vertices of $$\bigtriangleup$$ABC. The area of $$\bigtriangleup$$ABC is:

The vertices of a parallelogram are $$(3, -2),\;(4,0),\;(6, -3)$$ and $$(5, -5)$$. The diagonals intersect at the point $$M$$. The coordinates of the point $$M$$ are:

The coordinates of the points which divides the join of $$(-2, -2)$$ and $$(-5,7)$$ in the ratio $$2:1$$ is:

Mid-point of the line-segment joining the points $$(-5,4)$$ and $$(9, -8)$$ is:

Find the area of the triangle formed by joining the midpoints of the sides of the triangle whose vertices are $$(2,2)$$, $$(4,4)$$ and $$(2,6)$$.

Three consecutive vertices of a parallelogram are $$(1, -2)$$, $$(3,6)$$ and $$(5,10)$$. The coordinates of the fourth vertex are:

Find the coordinates of the point which divides the line segment joining the points $$A(4, -3)$$ and $$B(9,7)$$ in the ratio $$3:2$$

The coordinates of A and B are $$(1,2)$$ and $$(2,3)$$ respectively. Find the coordinates of R on the line segment AB so that $$\dfrac { AR }{ RB }=\dfrac { 4 }{ 3 }$$.