Differentiation Test 13

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Differentiation Test 13

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Weekly Quiz Competition

Question 1
1 / -0

A _____ is an arrangement of all or part of set of object in a definite order.

A
permutation

B
function

C
combination

D
factorial

Solution
Question 2
1 / -0

Find the number suitable for blank in given series.
1,2,3,5,8,13,21,___,55

A
35

B
33

C
36

D
34

Solution

The required number can be found by adding two numbers before it .
Examples : 3 can be found by adding two number before it.
i.e => (1+2) = 3
Similarly 5  can be found by adding two number before it.
i.e => (2+3) = 5 and so on.
In the same way the missing number can be found by adding  two number before it .
i.e => 13 + 21 = 34
The required number is 34. (Ans)
Question 3
1 / -0

33, 43, 65, 99, 145 ?

A
201

B
203

C
205

D
211

E
none of these

Solution

REF.Image
So Correct Answer is $$145+58= 203$$
Question 4
1 / -0

958, 833, 733, 658, 608 ?

A
577

B
583

C
567

D
573

E
none of these

Solution

$$958, 833, 733, 658, 608, - $$
$$a_{0}= 958$$
$$a_{1}= 833 = a_{0}- 125$$
$$a_{2}= 733=a_{1}-100$$
$$a_{3}= 658=a_{2}-75$$
$$a_{4}= 608 = a_{3}-50$$
These numbers are in A.P.
Where common difference = +25
Answer = $$a_{4}-25= 608-25=583$$
Question 5
1 / -0

If $$\left( {n + 1} \right)! = 12 \times (n - 1)!\;then\;n = $$

A
3

B
4

C
2

D
5

Solution

We have,
$$\left( {n + 1} \right)! = 12 \times (n - 1)!$$

$$(n + 1)\times n\times (n-1)! = 12 \times (n - 1)!$$

$$(n + 1)\times n = 12$$

$$n^2 +n- 12=0$$

$$n^2 +4n-3n- 12=0$$

$$(n+4)(n-3)=0$$

$$(n+4)\ne 0$$

So,
$$n-3=0$$
$$n=3$$

Hence, this is the answer.
Question 6
1 / -0

If D=4 and COVER = 63, then BASIC is equal to

A
49

B
50

C
34

D
55

Solution

In the alphabets D is 4th.
So, A = 1, B = 2 and C =3
So, COVER = 3+15+22+5+18 = 63
Therefore BASIC = 2+1+19+9+3 = 34
Question 7
1 / -0

if $$y=5x^2+8x$$ find $$\dfrac {dy}{dx}$$

A
$$10x+8$$

B
$$5x+8$$

C
$$10x^2+8x$$

D
none of these

Solution

The Equation is $$y=5x^2+8x$$
$$\dfrac {dy}{dx}=\dfrac d{dx}(5x^2+8x)\\\dfrac{dy}{dx}=10x+8$$
Question 8
1 / -0

The mid points of three sides of a triangle are (0, 1) (0, 2) and (0, 3). Area of this triangle.

A
3

B
0

C
1

D
None of these

Solution
Question 9
1 / -0

How many six letter words be made out of the letters of $$ASSIST$$ ? In how many words the alphabets $$S$$ alternates with other letters ?

A
$$120,6$$

B
$$720,\,12$$

C
$$120,\,12$$

D
$$720,\,24$$

Solution

The word ASSIST has 3 's' and 3 other characters (AIT).
Place the other 3 characters first. This can be done in 3! ways.
Now there are 4 spaces remaining (1234) mark as 1,2,3,4.
3 's' 5 can be placed at the spaces marked as 1,2,3 or at the spaces marked as 2,3,4 (2)was
Total no.of ways =3! .2$$=3\times 2\times 2=12$$
Total no.of ways =5!.$$=5\times 4\times 3\times 2=120.$$
$$\therefore$$ so, the answer is 120,12.
Question 10
1 / -0

If $$y=\log \sin x$$ find $$x$$ if $$y=0$$

A
$$\dfrac {\pi}2$$

B
$$\pi $$

C
$${\dfrac {\pi}3}$$

D
$$\dfrac {-\pi}2$$

Solution

$$y=\log \sin x\\y=0\\\log \sin x=\log 1\\\sin x=1\\\sin x=\sin \dfrac{\pi}2\\x=\dfrac{\pi}2$$

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Re-Attempt Weekly Quiz Competition

Differentiation Test 13

Result

Differentiation Test 13

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Rank

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SHARING IS CARING

Question 1

permutation

function

combination

factorial

Solution

Question 2

35

33

36

34

Solution

Question 3

201

203

205

211

none of these

Solution

Question 4

577

583

567

573

none of these

Solution

Question 5

3

4

2

5

Solution

Question 6

49

50

34

55

Solution

Question 7

$$10x+8$$

$$5x+8$$

$$10x^2+8x$$

none of these

Solution

Question 8

3

0

1

None of these

Solution

Question 9

$$120,6$$

$$720,\,12$$

$$120,\,12$$

$$720,\,24$$

Solution

Question 10

$$\dfrac {\pi}2$$

$$\pi $$

$${\dfrac {\pi}3}$$

$$\dfrac {-\pi}2$$

Solution

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