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Numerical Applications Test 13

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Numerical Applications Test 13
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Weekly Quiz Competition
  • Question 1
    1 / -0
    Rahul put his timepiece on the table in such a way that at $$6$$ P.M. hour hand points to North. In which direction the minute hand will point at $$9.15$$ P.M.?
    Solution
    At $$9.15$$ P.P., the minute hand will point towards west.

  • Question 2
    1 / -0
    Each of the questions given below consists of a question followed by three statements. You have to study the question and the statements and decide which of the statement(s) is$$/$$are necessary to answer the question.

    If both the pipes are opened, how many hours will be taken to fill the tank?
    I. The capacity of the tank is $$400$$ litres.
    II. The pipe A fills the tank in $$4$$ hours.
    III. The pipe B fiils the tank in $$6$$ hours.
    Solution
    II. Part of the tank filled by A in $$1$$ hour$$=\displaystyle\frac{1}{4}$$

    III. Part of the tank filled by B in $$1$$ hour$$=\displaystyle\frac{1}{6}$$

    $$(A+B)$$'s $$1$$ hour's work$$=\left(\displaystyle\frac{1}{4}+\frac{1}{6}\right)=\displaystyle\frac{5}{12}$$

    $$\therefore$$ A and B will fill the tank in $$\displaystyle\frac{12}{5}$$hrs$$=2$$hrs $$24$$min.

    So, II and III are needed.

    $$\therefore$$ Correct answer is (B).
  • Question 3
    1 / -0
    If the day before yesterday was thursday, when will sunday be ?
    Solution
    If day before yesterday was Thursday, then today is saturday.
    Tomorrow will be sunday.
  • Question 4
    1 / -0
    If the third day of a month is Tuesday, which of the following would be the 4th day before the 27th day of that month?
    Solution
    Dates on which Tuesday fall are 3,10,17, and 24
    Hence , the 27th day of the month will be (Tuesday + 3 days=)Friday
    $$\therefore$$  required day of the month = Friday - 4 = Monday
  • Question 5
    1 / -0
    If $$3$$ men or $$6$$ boys can do a work in $$20$$ days, how many days will $$6$$ men and $$8$$ boys take to do the same work?
    Solution
    $$3\ men = 6\ boys$$ or $$1\ man = 2\ boys$$.
    $$6\ men \ and\ 8\ boys = (2\times 6 + 8)$$ boys or $$20$$ boys.
    If $$6$$ boys can do a job in $$20$$ days
    $$\therefore 20$$ boys can do a job in $$\dfrac {6\times 20}{20} = 6\ days$$.
  • Question 6
    1 / -0
    How many men will be required to plough $$100$$ acres of land is $$10$$ days if $$10$$ men require $$8$$ days to plough $$20$$ acres of land?
    Solution
    AreaNo. of menNo. of days
    $$100$$$$x$$$$10$$
    $$20$$$$10$$$$8$$
    More men more area $$\therefore$$ direct variation
    More men less no. of days $$\therefore$$ inverse variation
    $$100 : 20 : : x : 10$$
    $$8 : 10$$
    $$100\times 8\times 10 = x \times 20\times 10$$
    $$\Rightarrow x = \dfrac {8000}{200} = 40$$
  • Question 7
    1 / -0
    Nitin correctly remembers that Nidhi's birthday is before Friday but after Tuesday. Dheeraj correctly remembers that Nidhi's birthday is after Wednesday but before Saturday. On which of the following days does Nidhi's birthday definitely fall?
    Solution
    According to Nitin, Nidhi's birthday falls on Wednesday or Thursday    ---------(i)
    According to Dheeraj , Nidhi's birthday falls on Thursday or Friday      ---------(ii)
    From (i) and (ii), Nidhi's birthday falls on Thursday.
  • Question 8
    1 / -0
    A, B, C can do a piece of work individually in $$8, 10$$ and $$15$$ days respectively. A and B start working by A quits after working for $$2$$ days. After this, C joins B till the completion of work. In how many days will the work be completed?
    Solution
    Work done by A in $$1\ day = \dfrac {1}{8}$$
    Work done by B in $$1\ day = \dfrac {1}{10}$$
    Work done by C in $$1\ day = \dfrac {1}{15}$$
    Work done by A and B together in $$1\ day = \dfrac {1}{8} + \dfrac {1}{10}$$
    $$= \dfrac {5 + 4}{40} = \dfrac {9}{40}$$
    $$\therefore$$ In $$2$$ days A and B complete $$2\times \dfrac {9}{40} = \dfrac {9}{20}$$ of work
    Work remaining $$= 1 - \dfrac {9}{20} = \dfrac {11}{20}$$
    Work done by B and C together in $$1\ day$$
    $$= \dfrac {1}{10} + \dfrac {1}{15}$$
    $$= \dfrac {3 + 2}{30} = \dfrac {5}{30} = \dfrac {1}{6}$$
    Let no. of days be n.
    $$\therefore n\times \dfrac {1}{6} = \dfrac {11}{20}$$
    $$n = \dfrac {11}{20}\times 6 = \dfrac {33}{10}days$$
    Total no. of days $$= \left (2 + \dfrac {33}{10}\right ) = \dfrac {53}{10}$$
  • Question 9
    1 / -0
    Sandhya's birthday falls on 15th August and Minu's birthday falls on 25th June. If Minu's birthday was on Wednesday, what was the day on Sandhya's birthday in the same year?
    Solution
    Total days from 25th June to 15th August = 5 + 31 + 15 = 51 days
    $$51 \div 7 =7$$    weeks and 2 days 
    $$\therefore$$     August 15 = Wednesday + 2 = Friday
  • Question 10
    1 / -0
    If day after tomorrow is saturday, what day was 3 days before yesterday ?
    Solution
    Day after tomorrow is Saturday. So, today is thursday, then yesterday was wednasday and 3 days before wednasday was sunday.
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