Numerical Applications Test 18

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Numerical Applications Test 18

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Weekly Quiz Competition

Question 1
1 / -0

Find the mean of $$ 43,54,64,53,36.$$

A
$$50$$

B
$$ 40$$

C
$$60$$

D
$$ 30$$

Solution

Sum of observations $$=$$ $$43+54+64+53+36$$
$$=250$$

No . of observations $$=$$ $$5$$

Mean of data $$=\dfrac{250}{5}$$
$$=50$$
Question 2
1 / -0

The A.M. of $$a + 2, a, 2-a$$ is

A
$$a$$

B
$$\cfrac { a+4 }{ 3 } $$

C
$$\cfrac { a-4 }{ 3 } $$

D
$$\cfrac { a }{ 2 } $$

Solution

Given values are : $$a+2, a, 2-a$$

Arithmetic Mean, $$AM = \dfrac{a+2+a+2-a}{3}$$

$$AM = \dfrac{a+4}{3}$$

Hence, option (B) is corret
Question 3
1 / -0

The mean of $$56,15,48,49,52,57,30,51,42,50$$ is

A
45

B
50

C
55

D
None of these

Solution

Given data is $$56,15,48,49,52,57,30,51,42,50$$
No .of observations $$10$$
Sum of observations is $$56+15+48+49+52+57+30+51+42+50=450$$
Mean of the data is $$\dfrac{450}{10}=45$$
Question 4
1 / -0

The mean of $$33,53,32,35,47$$ is

A
$$40$$

B
$$56$$

C
$$55$$

D
$$6^{6}-6!$$

Solution

Given observations $$33,53,32,35,47$$
no. of observations is $$5$$
Sum of observations is $$33+53+32+35+47=200$$
Mean is $$\dfrac{200}{5}=40$$
Question 5
1 / -0

Find the mean of $$22,16,19,12,26,32,87,58$$

A
34

B
32

C
43

D
none of these

Solution

given observations $$22,16,19,12,26,32,87,58$$
No .of observations $$8$$
Sum f observations $$22+16+19+12+26+32+87+58=272$$
Mean is given as $$\dfrac{272}8=34$$
Question 6
1 / -0

Find the mean of $$16,29,60,18,27$$

A
30

B
40

C
50

D
10

Solution

The given data is $$16,29,60,18,27$$
The sum of observations is $$16+29+60+18+27=150$$
The mean is given as $$\dfrac{150}{5}=30$$
Question 7
1 / -0

Find the mean of $$35,34,25,52,27,23,24,36$$

A
32

B
28

C
24

D
30

Solution

Given data $$35,34,25,52,27,23,24,36$$
No .of observations $$8$$
Sum of observations $$35+34+25+52+27+23+24+36=256$$
Mean is $$\frac{256}{8}=32$$
Question 8
1 / -0

Find the mean of $$36,40,32,48,44$$

A
40

B
45

C
50

D
35

Solution

No .of observations $$5$$
Sum of observations $$36+40+32+48+44=200$$
Mean $$\dfrac{200}{5}=40$$
Question 9
1 / -0

Find the mean of $$31,45,84,23,67$$

A
48

B
50

C
52

D
None.

Solution

Given data $$31,45,84,23,67$$
The sum of observations $$31+45+84+23+67=240$$
The mean $$\dfrac {240}{5}=48$$
Question 10
1 / -0

How many six letter words be made out of the letters of $$ASSIST$$ ? In how many words the alphabets $$S$$ alternates with other letters ?

A
$$120,6$$

B
$$720,\,12$$

C
$$120,\,12$$

D
$$720,\,24$$

Solution

The word ASSIST has 3 's' and 3 other characters (AIT).
Place the other 3 characters first. This can be done in 3! ways.
Now there are 4 spaces remaining (1234) mark as 1,2,3,4.
3 's' 5 can be placed at the spaces marked as 1,2,3 or at the spaces marked as 2,3,4 (2)was
Total no.of ways =3! .2$$=3\times 2\times 2=12$$
Total no.of ways =5!.$$=5\times 4\times 3\times 2=120.$$
$$\therefore$$ so, the answer is 120,12.

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Numerical Applications Test 18

Result

Numerical Applications Test 18

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SHARING IS CARING

Question 1

$$50$$

$$ 40$$

$$60$$

$$ 30$$

Solution

Question 2

$$a$$

$$\cfrac { a+4 }{ 3 } $$

$$\cfrac { a-4 }{ 3 } $$

$$\cfrac { a }{ 2 } $$

Solution

Question 3

45

50

55

None of these

Solution

Question 4

$$40$$

$$56$$

$$55$$

$$6^{6}-6!$$

Solution

Question 5

34

32

43

none of these

Solution

Question 6

30

40

50

10

Solution

Question 7

32

28

24

30

Solution

Question 8

40

45

50

35

Solution

Question 9

48

50

52

None.

Solution

Question 10

$$120,6$$

$$720,\,12$$

$$120,\,12$$

$$720,\,24$$

Solution

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