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Functions Test 39

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Functions Test 39
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  • Question 1
    1 / -0
    Let $$f(x)=\dfrac{x}{(x^2-1)}$$. Then, dom $$(f)=?$$
    Solution
    $$f(x)=\dfrac{x}{(x^2-1)}$$

    $$f(x)$$ is not defined when $$(x^2-1)=0$$,

    i.e., when $$(x-1)(x+1)=0$$,

    i.e., when $$x=1$$ or $$x=-1$$.

    $$\therefore dom(f)=R-[1, -1]$$.
  • Question 2
    1 / -0
    Let $$f(x)=\dfrac{\sin^{-1}x}{x}$$. Then, dom $$(f)=?$$
    Solution

  • Question 3
    1 / -0
    If $$f(x)=\sqrt[3]{3-x^3}$$ then $$(f o f)(x)=?$$
    Solution

  • Question 4
    1 / -0
    Let $$f(x)=e^{\sqrt{x^2-1}}\cdot log (x-1)$$. Then, dom $$(f)=?$$
    Solution

  • Question 5
    1 / -0
    Let $$f(x)=\cos^{-1}2x$$. Then, dom $$(f)=?$$
    Solution
    $$\sin^{-1}2x$$ is defined only when $$2x\in[-1, 1]\Rightarrow x\in\left[\dfrac{-1}{2}, \dfrac{1}{2}\right]$$.
  • Question 6
    1 / -0
    Let $$ f : R \rightarrow R : f(x) =x +1 $$ and $$ g : R \rightarrow R : g(x) = 2x -3 $$.
    Find $$(f +g) (x)$$.
    Solution
    Given ,
    $$f(x)=x+1,g(x)=2x-3$$

    $$\implies (f+g)x=f(x)+g(x)=x+1+2x-3=3x-2$$
  • Question 7
    1 / -0
    Let $$f(x)=\sqrt{\log(2x-x^2)}$$. Then, dom $$(f)=?$$
    Solution
    $$f(x)$$ is defined only when $$\log (2x-x^2) \geq 0$$

    $$\Rightarrow (2x-x^2)\geq 1$$

    $$\Rightarrow (1+x^2-2x)\leq 0$$

    $$\Rightarrow (1-x)^2\leq 0$$

    Since, any square no. can never be negative

    $$\therefore (1-x)=0$$

    $$\Rightarrow x=1$$.

    $$\therefore dom(f)=\{1\}$$.
  • Question 8
    1 / -0
    Let $$f(x)=x^2$$. Then, dom $$(f)$$ and range(f) are respectively.
    Solution

  • Question 9
    1 / -0
    If $$\displaystyle f(x) = | x - 2 |$$ and $$ g(x) = fof\,(x) $$ , then for $$ x > 20 , {g}\,'(x) = $$ 

    Solution

  • Question 10
    1 / -0
    If [.] denotes the greatest integer function then the domain of the real valued function $$\log_{[x+1/2]}\left| x^2 -x-2\right| $$ is
    Solution

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