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Straight Lines Test 30

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Straight Lines Test 30
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  • Question 1
    1 / -0
    If $$9@ 3 = 12, 15 @ 4 = 22, 16 @ 14 = 4$$, then what is the value of $$6 @ 2 = ?$$
    Solution
    $$(9 - 3) \times 2 = 12, (15 - 4) \times 2$$
    $$= 22, (16 - 14) \times 2 = 4$$
    Hence, $$(6 - 2) \times 2 = 8$$.
  • Question 2
    1 / -0
     5 2 7
     ? 3 1
     4 5 2
     -15 7 13
    Select the missing number from the given alternatives.
    Solution
    Columnwise
    First Number x Third Number - Second Number = Lowermost Number

    First Column
    $$5 \times 4 - ? = 15 \Rightarrow 20 - ? = 15$$
    $$\therefore ? = 20 - 15 = 5$$

    Second Column
    $$ 2 \times 5 - 3 = 10 - 3 = 7$$

    Third Column
    $$ 7 \times 2 - 1 = 14 - 1 = 13$$
  • Question 3
    1 / -0
    Select the missing number from the given alternatives.
    $$3$$$$4$$$$2$$$$14$$
    $$6$$$$5$$$$4$$$$44$$
    $$5$$$$2$$$$7$$?
    Solution
    $$3\times 2 + 4\times 2 = 6 + 8 = 14$$
    $$6\times 4 + 5\times 4 = 24 + 20 = 44$$
    Hence, $$5\times 7 + 2 \times 7 = 35 + 14 = 49$$.
  • Question 4
    1 / -0
    Directions for questions 1 to 3: Find the related word/ letters/numbers from given alternatives.
    12:72::8:?
    Solution
    12 $$\times \, \frac{12}{2}$$ = 72 similarly, 8 $$\times \, \frac{8}{2}$$ = 32
  • Question 5
    1 / -0
    If $$12\times 16 = 188$$ and $$14\times 18 = 248$$, then find the value of $$16\times 20 = ?$$
    Solution
    $$12\times 16 = 192 - 4 = 188$$
    $$14\times 18 = 252 - 4 = 248$$
    $$16\times 20 = 320 - 4 = 316$$.
  • Question 6
    1 / -0
    Select the missing number from the given alternatives.

    Solution
    48 $$\div$$ 2 = 24;
    24 $$\times$$ 3 = 72: 72 $$\div$$ 2 = 36;
    36 $$\div$$ 3 = 108; 108 $$\div$$ 2 = 54.
  • Question 7
    1 / -0
    Choose the correct answer from the alternatives given.
    If $$1^2+2^2$$ +.... + $$x^2$$ = $$\frac{x(x + 1)(2x + 1)}{6}$$then $$1^2$$ 
    + $$3^2$$+ $$5^2$$ + .... + $$19^2$$ is equal to
    Solution
    $$(1^2+3^2+5^2+...........+19^2)$$
    = $$\displaystyle\, $$(1^2$$ \, + \, $$2^2$$ \, + \, $$3^2$$ \, + \, ........... \, + \, 20^2)  \, - \, (2^2 \, + \, 4^2 \, + \, 6^2 \, + \, ........... \, + \, 20^2)$$
    = $$\displaystyle\, (1^2 \, + \, 2^2 \, + \, 3^2 \, + \, .......... \, + \, 20^2) - 4(1 \, + \, 2^2 \, + \, 3^2 \, + \, .......... \, + \, 10^2)$$
    Using the formula,
    $$\displaystyle\, = \frac{20 \times  21 \times  41}{6} - 4 \left ( \frac{10 \times  11 \times  21}{6} \right ) = 2870 - 1540 = 1330$$

  • Question 8
    1 / -0
    Choose the correct answer alternatives given.
    Select the missing number from the given alternatives.

    Solution
    80 = 8 $$\times$$ (8 + 2)
    143 = 11 $$\times$$ (11 + 2)
    323 = ? $$\times$$ (? + 2)
    $$\therefore$$ ? = 17
  • Question 9
    1 / -0
    If $$1^{3} + 2^{3} + .... + 10^{3} = 3025$$, then the value of $$2^{3} + 4^{3} + ..... + 20^{3}$$ is
    Solution
    Given that, $$1^{3} + 2^{3} + .... + 10^{3} = 3025$$
    Now, $$2^{3} + 4^{3} + .... + 20^{3}$$
    $$= 2^{3} (1 + 2^{3} + .... + 10^{3}) = 8\times 3025 = 24200$$.
  • Question 10
    1 / -0
    Arrange these numbers in ascending order. 
    $$756, 567, 657, 676$$ 
    Solution
    $$\Rightarrow$$  Numbers are said to be in ascending order when they are arranged from the smallest to the largest number.
    $$\Rightarrow$$  The numbers which we have to arrange in ascending order are $$756,\,567,\,657$$ and $$676$$
    $$\Rightarrow$$  $$567<657<676<756$$
    $$\therefore$$  Ascending order $$=567,\,657,\,676,\,756$$
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