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Respiration in Plants Test - 61

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Respiration in Plants Test - 61
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Weekly Quiz Competition
  • Question 1
    1 / -0
    Pasteur effect can be studied in case of __________.
  • Question 2
    1 / -0
    Enzyme used in conversion of glucose into glucose 6-phosphate is
    Solution
    Glucose is a 6 carbon organic substrate that undergoes glycolysis for the release of energy during cellular respiration. Glucose is first phosphorylated to glucose 6-phosphate by an enzyme called 'Hexokinase' in the presence of Mg2+. So, the answer is 'Hexokinase'.
  • Question 3
    1 / -0
    Which is wrong about Krebs cycle?
    Solution
    Krebs cycle also called as citric acid cycle occurs in the mitochondrial matrix and starts with 6 carbon compound but not linked glycolysis through malic acid.
    So the correct option is 'Glycolysis is linked to it through malic acid.'
  • Question 4
    1 / -0

    Choose the correct labeling

    Solution
    • In the fermentation process pyruvate is decarboxylated to an acetaldehyde releasing carbon dioxide and acetaldehyde is catalyzed by alcohol dehydrogenase to produce ethanol.

    So, the correct option is 'Ethanol, Acetaldehyde, and CO$$_2$$.'
  • Question 5
    1 / -0
    3-phosphoglyceraldehyde is oxidized in glycolysis to form
    Solution
    Glycolysis is a metabolic process in which one glucose molecule is converted into 2 puruvate molecules under aerobic condition. During the sixth step, 3-phosphoglyceraldehyde is oxidized to 1,3-biphsosphoglycerate in presence of enzyme glyceraldehyde-3-phosphate dehydrogenase. During this reaction, NAD$$^+$$ is converted to NADH.
    Thus, the correct answer is '1, 3-biphosphoglycerate.'

  • Question 6
    1 / -0
    A value of RQ less than one means
    Solution
    When the RQ value is less than one for fats,  as fats consume more oxygen for respiration than carbohydrates.
    So the correct option is 'Oxidation of respiratory substrate consume more O2 than CO2 released.'
  • Question 7
    1 / -0
    For formation of ethanol, pyruvic acid is first changed to acetaldehyde by enzyme
    Solution
    Alcoholic fermentation employs the conversion of pyruvic acid to ethanol for the release of energy. This is an incomplete oxidation in which aldehyde is first formed as an intermediate which is then further oxidised to alcohol. Pyruvic acid to acetaldehyde conversion is brought about by pyruvate decarboxylase which releases CO2.
    So the answer is 'Pyruvate decarboxylase'.
  • Question 8
    1 / -0
    Succinate + FAD forms
    Solution
    In Krebs' cycle, succinate is dehydrogenated to fumarate by the enzyme succinate dehydrogenase. The hydrogen that is released reduces FAD to FADH2.
    So the answer is 'Fumarate + FADH2'.
  • Question 9
    1 / -0
    An enzyme not used in Krebs cycle is
    Solution
    Aconitase, decarboxylase, and fumarase are the enzymes used in the Krebs cycle but enzyme Aldolase is absent in Krebs cycle but present in glycolysis.
    So the correct option is 'Aldolase.'
  • Question 10
    1 / -0
    Acetyl CoA forms a 6-C compound after combining with
    Solution
    Pyruvic acid is converted to Acetyl CoA (2 C) by the link reaction through the pyruvate dehydrogenase complex. Acetyl CoA can now enter Krebs' cycle by combining with oxaloacetic acid which is a 4 carbon compound. So the citric acid that is formed is a 6 carbon compound.
    So, the correct answer is 'Oxaloacetic acid'.
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