Organic Chemistry Some Basic Principles and Techniques Test

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Organic Chemistry Some Basic Principles and Techniques Test - 65

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Weekly Quiz Competition

Question 1
1 / -0

Major product of the reaction is :

A

B

C

D

Solution
Question 2
1 / -0

The major hydrolysis product of the following reaction will be:

A

B

C

D

Solution
Question 3
1 / -0

4-Formylbenzoic acid on treatment with one equivalent of hydrazine followed by heating with alcoholic KOH gives the major product:

A

B

C
potassium salt of m-toluic acid

D
none of these

Solution

4-formylbenzoic acid when reacts with hydrazine $$(NH_2-NH_2)$$ it forms the corresponding hydrazone.
When this compound is treated with $$KOH$$ it forms potassium salt of p-toluic acid.
Question 4
1 / -0

What is the major product of the reaction?

A

B

C

D
Question 5
1 / -0

Above Gauche form is stable when Z is:

A
$$-C{ H }_{ 3 }$$

B
$$-Et$$

C

D
$$-Ph$$
Question 6
1 / -0

$$IUPAC$$ name of $$[VO(O_{2})(acac)_{2}]$$ is

A
bis(acetylacetonato)oxoperoxonanadium(VI)

B
bis(acetylacetonato)oxoperoxonanadium(V)

C
bis(acetylacetonato)oxoperoxonanadium(VIII)

D
bis(acetylacetonato)oxoperoxonanadium(IV)

Solution
Question 7
1 / -0

Which of the following reactions represent major products?

A

B

C

D
Question 8
1 / -0

The structure of (S) - 2 - chlorobutane is best represented by :

A
$$CH_3\overset{Cl}{\overset{|}{Cl}}HCH_2CH_3$$

B

C

D
Question 9
1 / -0

Choose the correct statement regarding the preparation of Lassaigne's extract of a given organic compound.

A
Li can be used on the place of Na

B
Li cannot be used on the place of Na because its compound are covalent in nature

C
Both A and B

D
None of these
Question 10
1 / -0

The correct order of reactivity of the following compounds towards aqueous NaCN will be:

A

B
$$CH_2 = CH - CH_2 - Cl$$

C
$$CH_3 - \overset{Cl}{\overset{|}{Cl}} - CH_3$$

D
$$CH_2 = CH - CH_2 - Br$$

Solution

$$CH_2=CH-CH_2-Br$$
Allyl bromide is highly reactive towards aqueous $$KCN$$. As, allylic cation form is very stable due to the resonance. Also, leaving group ability of $$Br^{\circleddash}$$ is greater than that of chloride $$Cl^{\circleddash}$$ .