Hydrocarbons Test

Result

Hydrocarbons Test - 36

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Weekly Quiz Competition

Question 1
1 / -0

How many cyclic and alkene isomers of $$C_4H_8$$ are possible? ( Excluding stereoisomers)

A
$$3$$

B
$$4$$

C
$$5$$

D
$$6$$

Solution
Question 2
1 / -0

How many optical isomers are possible on monochlorination of $$2-$$methyl butane

A
$$2$$

B
$$4$$

C
$$6$$

D
$$8$$

Solution
Question 3
1 / -0

From which one of the following both ethylene and acetylene could be prepared in a single step?

A
$$CH_{3}CH_{2}OH$$

B
$$Br - CH_{2} - CH_{2} - Br$$

C
$$CH_{3}CH_{2}Br$$

D
$$Br - CH = CH_{2}$$

E
$$CH_{3}COOH$$

Solution

Ethylene is obtained through dehalogenation while acetylene is obtained thorough a double dehydrohalogenation.

$$(Br)CH_2(Br) \xrightarrow {NaNH_2} CH \equiv CH$$
Question 4
1 / -0

Here the major product $$X$$ and $$Y$$ are

A
$$CIC{H_2} - C{H_2}Cl,\,\,ClC{H_2} - C{H_2}Cl$$

B
$$CIC{H_2} - C{H_2}Cl,\,\,ClC{H_2} - C{H_2}OH$$

C
$$C{I_2}C = CC{l_2},\,\,ClCH = CHCl$$

D
$$C{l_2}C = CC{l_2},ClC{H_2} - C{H_2}OH$$

Solution
Question 5
1 / -0

By which of the following reagent butanoic acid is converted into butane

A
Red P / HI

B
NaOH / CaO

C
$${\text{C}}{{\text{H}}_3}{\text{MgBr}}$$

D
Na/ ether

Solution
Question 6
1 / -0

Identify major product $${{\text{P}}_{\text{3}}}$$:

A

B

C

D

Solution
Question 7
1 / -0

Acetylene reacts with excess of hypochiorous acid to produce

A
Acetylene tetrachloride

B
Acetylene chlorohydrin

C
Acetaldehyde

D
Dichloroacetaldehyde.

Solution
Question 8
1 / -0

$$C{H_3} - CH = C{H_2}\xrightarrow[{\left( 2 \right)C{H_2}C{O_2}T}]{{\left( 1 \right)B{D_3},THF}}\left( A \right):$$ Product $$A$$ of the above reaction is

A
$$C{H_3} - CHD - C{H_2}D$$

B
$$C{H_3} - CHT - C{H_2}T$$

C
$$C{H_3} - CHD - C{H_2}T$$

D
$$C{H_3} - CHT - C{H_2}D$$

Solution
Question 9
1 / -0

An alkene of molecular formula $$C_{9}H_{18}$$ on ozonolysis gives 2,2-dimethylpropanal and butan-2-one, then the alkene is

A
2,2,4-trimethylhex-3-ene

B
2,2,6-trimethylhex-3-ene

C
2,3,4-trimethylhex-2-ene

D
2,2,4-trimethylhex-2-ene

Solution

Correct answer is option A.
Question 10
1 / -0

In which case butane is formed ?

A
$$ 2C_2H_5 -CI+Na $$

B
$$ C_2H_5COOH+Na_2CO_3 $$

C
$$ { CH }_{ 3 }{ CH }_{ 2 }\overset { \overset { O }{ || } }{ C } -OH+H_{ 2 }O$$

D
$$ CH_2=CH_2+H_2SO_4 $$

Solution