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     In a battle 70% of combatants lost one eye , 80% an ear , 75% an arm , 85% a leg ,x% lose all the four limbs. The minimum value of x is :

    Solution

    Given that percentage of combatants who lost one eye=70%,  an ear=80% and an arm =75% and a leg =85%

    Hence we get  percentage of combatants who lost one eye and one ear =(70%+80%)-100%=50%

    percentage of combatants who lost one eye  one ear and one arm =(50%+75%)-100%=25%

    Similarly percentage of combatants who lost one eye  one ear  one arm  and one leg =(25%+85%)-100%=10%

    Hence we get percentage of combatants who lost all 4 limbs =10%

    Hence if x% represent the  percentage of combatants who lost all 4 limbs we get minimum value of x=10

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