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Sets Test - 5

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Sets Test - 5
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  • Question 1
    1 / -0

    If A and B are two sets, then A ∩ ( A ∪ B )′ is equal to

    Solution

    A ∩ ( A ∪ B )′ = ϕ

    since ( A ∪ B )′ Set represent the element which are not belongs to it,so there is no common element with the set A.So the answer is null set

  • Question 2
    1 / -0

    If A is any set , then

    Solution

    A ∪ A′ = { x ∈ U: x ∈ A } ∪ { x ∈ U: x ∉ A } = U

  • Question 3
    1 / -0

    If A and B be any two sets , then ( A ∪ B )′  is equal to

    Solution

    x ∈ ( A ∪ B )′

    ⇒x ∉ ( A ∪ B )

    ⇒x ∉ A or x ∉ B 

    ⇒ x ∈ A′ and x ∈ B′

    ⇒x ∈ A′ ∩ B′

    ⇒( A ∪ B )′ ⊆ A′ ∩ B′

    Similarly we can show ( A′ ∩ B ′) ⊆ ( A ∪ B )′

    so ( A ∪ B )′ = ( A′ ∩ B′ )

  • Question 4
    1 / -0

    Let A = { 1,2,3,4} , B = { 2,3,4,5,6 } , then ( A ∩ B ) is equal to :

    Solution

    Here A = { 1,2,3,4} and B = {2,3,4,5,6}

    A ∩ B = {1,2,3,4} ∩ {2,3,4,5,6}

    ={2,3,4}
     

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