Relations and F...

If $$f(x+1)=3x-9$$, then what will be the value of $$f\left( { x }^{ 2 }-1 \right) $$?

On differentiating an identity function, we get?

If $$f(x + 1) = 3x - 9$$, then what will be the value of $$f(x^{2} - 1)$$?

If $$\left |x^2-2x-8  \right | + \left |x^2+x-2  \right | = 3 \left |x +2  \right |$$, then the set of all real values of x is

If log $$x - 5$$ log $$3$$ = $$-2$$, then x equals

If $$f(x) = \dfrac {x(x - 1)}{2}$$ then $$f(x + 2)$$ equals.

If $${C}_{r}$$ stands for $${ _{  }^{ n }{ C } }_{ r }$$ then $$\left( { C }_{ 0 }+{ C }_{ 1 } \right) +\left( { C }_{ 1 }+{ C }_{ 2 } \right) +....\left( { C }_{ n-1 }+{ C }_{ n } \right) \quad $$ is equal to

Let $$A=\left\{ a,b,c \right\} $$ and $$B=\left\{ 1,2 \right\} $$. Consider a relation $$R$$ defined from set $$A$$ to set $$B$$. Then $$R$$ is equal to set

If $$f(x)=\cos { \left( \log { x }  \right)  } $$ then $$f(x)f(y)-\cfrac { 1 }{ 2 } \left[ f\left( \cfrac { x }{ y }  \right) +f(xy) \right] $$ has value

If $$f(x)=\cfrac { x }{ { x }^{ 2 }+1 } $$ is increasing function then the value of $$x$$ lies in