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What are the direction ratios of the line of intersection of the planes x = 3z + 4 and y = 2z - 3?

The ratio in which the line joining the points \((1,2,3)\) and \((-3,4,-5)\) is divided by the \(x y\)-plane is:

The points \((3,2,0),(5,3,2)\) and \((-9,6,-3)\), are the vertices of a triangle \(ABC \cdot AD\) is the internal bisector of \(\angle BAC\) which meets \(BC\) at D. Then the co-ordinates of \(D\), are:

Find the distance between the planes 2x - 3y + 6z - 5 = 0 and 6x - 9y + 18z + 20 = 0.

The equation of the plane containing the line \(2 x-5 y+z=3, x+y+4 z=\) 5 and parallel to the plane \(x+3 y+6 z=1\) is:

The equation of the set of points which are equidistant from the points (1, 2, 3) and (3, 2, −1) is:

The distance between the \(x\)-axis and the point \((3,12,5)\) is:

In a three dimensional space, the equation 3x – 4y = 0 represents:

P is a point on the line segment joining the points (3, 2, -1) and (6, -4, -2). If x coordinate of P is 5, then its y coordinate is:

If the endpoints of a diagonal of a square are (1, -2, 3) and (2, -3, 5) then the length of the side of a square is: