Waves Test - 69...

A simple harmonic progressive wave is represented by the equation : $$ y = 8 \sin 2 \pi \left (0.1x - 2t  \right )$$ where x and y are in cm and t is in seconds. At any instant the phase difference between two particles separated by 2.0 cm in the x-direction is     [MP PMT 2000]

The displacement of the interfering light waves are $$y_1 = 4 sin\omega t$$ and $$y_2=3 sin \left(\omega t + \dfrac{\pi}{2}\right)$$ . What is the amplitude of the resultant wave

The amplitude of a wave represented by displacement equation $$y = \dfrac{1}{\sqrt{a}} sin\omega t \pm \dfrac{1}{\sqrt{b}} cos \omega t$$will be

The path difference between the two waves $$y_1 = a_1 \sin \left (\omega t - \frac{2 \pi x} {\lambda}  \right )$$ and $$y_2 = a_2 \cos \left (\omega t - \frac{2 \pi x} {\lambda} + \phi \right )$$            [MP PMT 1994]

If two waves having amplitudes $$2A$$ and $$A$$ and same frequency andvelocity, propagate in the same direction in the same phase, the resulting amplitude will be

Two waves of frequencies $$20 Hz$$ and $$30 Hz$$. Travels out from a common point. The phase difference between them after $$0.6$$ sec is

Two waves$$y_1 = A_1 sin(\omega t -\beta_1) y_2 = A_2 sin(\omega t - \beta_2)$$ Superimpose to form a resultant wave whose amplitude is [CPMT 1999]

Two waves of same frequency and intensity superimpose with each other in opposite phases, then after superposition the

The phase difference between two points separated by 0.8 m in a wave of frequency 120 Hz is $$90^{0}$$. Then the velocity of wave will be

Two waves are represented by $$y_1 = a sin \left(\omega t +\dfrac{\pi}{6}\right)$$and $$y_2 = a cos \omega t$$ What will be their resultant amplitude