Units and Measurements Test

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Units and Measurements Test - 11

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Weekly Quiz Competition

Question 1
1 / -0

The number of significant digits in 0.2370 is

A
6

B
3

C
4

D
5
Solution
There are three rules on determining how many significant figures are in a number:
- Non-zero digits are always significant.
- Any zeros between two significant digits are significant.
- A final zero or trailing zeros in the decimal portion ONLY are significant.
So keeping these rules in mind, there are 4 significant digit.
Question 2
1 / -0

The number of significant digits in 6.320 J is

A
5

B
6

C
4

D
3
Solution
There are three rules on determining how many significant figures are in a number:
- Non-zero digits are always significant.
- Any zeros between two significant digits are significant.
- A final zero or trailing zeros in the decimal portion ONLY are significant.
So keeping these rules in mind, there are 4 significant digit.
Question 3
1 / -0

The number of significant digits in 6.032 N m⁻² is

A
4

B
6

C
3

D
5
Solution
There are three rules on determining how many significant figures are in a number:
- Non-zero digits are always significant.
- Any zeros between two significant digits are significant.
- A final zero or trailing zeros in the decimal portion ONLY are significant.
So keeping these rules in mind, there are 4 significant digit.
Question 4
1 / -0

The number of significant digits in 0.0006032 m² is

A
5

B
4

C
6

D
3
Solution
There are three rules on determining how many significant figures are in a number:
- Non-zero digits are always significant.
- Any zeros between two significant digits are significant.
- A final zero or trailing zeros in the decimal portion ONLY are significant.
So keeping these rules in mind, there are 4 significant digit.
Question 5
1 / -0

The mass of a box measured by a grocer’s balance is 2.300 kg. Two gold pieces of masses 20.15 g and 20.17 g are added to the box. What is the difference in the masses of the pieces to correct significant figures?

A
0.022 g

B
0.01 g

C
0.02 g

D
0.019 g

Solution

Difference in masses = 20.17 – 20.15 = 0.02 g

In subtraction, the final result should retain as many decimal places as there are in the number with the least decimal places.
Question 6
1 / -0

The length, breadth and thickness of a rectangular sheet of metal are 4.234 m, 1.005 m, and 2.01 cm respectively. Give the area of the sheet to correct significant figures.

A
8.72 m²

B
8.722 m²

C
8.7221 m²

D
8.8 m²

Solution

length, l = 4.234 m

breadth,b = 1.005 m

thickness, t = 2.01 cm = 2.01 × 10^-2 m Area of the sheet = 2 (l × b + b × t + t × l) = 2 (4.234 × 1.005 + 1.005 × 0.0201 + 0.0201 × 4.234) = 2 (4.3604739) = 8.7209478 m²

As area can contain a maximum of three significant digits, therefore, rounding off, we get Area = 8.72 m²
Question 7
1 / -0

The length, breadth and thickness of a rectangular sheet of metal are 4.234 m, 1.005 m, and 2.01 cm respectively. Give the volume of the sheet to correct significant figures.

A
0.0755 m³

B
0.08552 m³

C
0.1855 m3

D
0.0855 m3

Solution

length, l = 4.234 m

breadth,b = 1.005 m

thickness, t = 2.01 cm = 2.01 × 10^-2 m

volume = l × b × t

=> V = 4.234 × 1.005 × 0.0201 = 0.0855289 = 0.0855 m³ (Significant Figures = 3)
Question 8
1 / -0

A book with many printing errors contains four different formulas for the displacement y of a particle undergoing a certain periodic motion. Choose the correct formula

A
y = a sin vt

B
y = a sin 2 π t

C
y = a sin 2πt/T

D
y = (a/T) sin t/a

Solution

Dimension of y = M⁰ L¹ T⁰

Dimension of a = M⁰L¹T⁰

Dimension of sin 2πt/T= M⁰L⁰T⁰

Dimension of L.H.S = Dimension of R.H.S Hence, the given formula is dimensionally correct.

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Re-Attempt Weekly Quiz Competition

Units and Measurements Test - 11

Result

Units and Measurements Test - 11

Score

-

Rank

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SHARING IS CARING

Question 1

6

3

4

5

Solution

Question 2

5

6

4

3

Solution

Question 3

4

6

3

5

Solution

Question 4

5

4

6

3

Solution

Question 5

0.022 g

0.01 g

0.02 g

0.019 g

Solution

Question 6

8.72 m2

8.722 m2

8.7221 m2

8.8 m2

Solution

Question 7

0.0755 m3

0.08552 m3

0.1855 m3

0.0855 m3

Solution

Question 8

y = a sin vt

y = a sin 2 π t

y = a sin 2πt/T

y = (a/T) sin t/a

Solution

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8.72 m²

8.722 m²

8.7221 m²

8.8 m²

0.0755 m³

0.08552 m³