Laws of Motion ...

A road is $$8\ m$$ wide. Its radius of curvature is $$40\ m$$. The outer edge is above the lower edge by  distance of $$1.2\ m$$. The most suited velocity on the road is nearly:

A vehicle is at rest on a banked road with angle of banking $$\theta$$. The normal reaction of the vehicle is $${N}_{1}$$. When the vehicle takes a turn on the same road the normal reaction is $${N}_{2}$$. Then $${N}_{1}/{N}_{2}$$ is equal to:

A boy is swinging in a swing. If he stands the time period will

A particle is moving in a vertical circle the tension in the string when passing through two position at angle $${30}^{o}$$ and $${60}^{o}$$ from vertical lowest position are $${T}_{1}$$ and$${T}_{2}$$ respectively then-

A weightless thread can support tension upto $$30N$$. A particle of mass $$0.5kg$$ is tied to it and is revolved in a circle of radius $$2m$$ in a vertical plane. If $$g=10m/{s}^{2}$$, then the maximum angular velocity of the stone will be

A hammer of mass 1 kg moving with a speed of 6 m/s strikers a wall and comes to rest in 0.1 s, calculate Retarding force that stops the hammer.

A boy is swinging on a swing such that his lowest and highest positions are at heights of $$2m$$ and $$4.5m$$ respectively. His velocity at the lowest position is:

A stone of mass $$0.2kg$$ is tied to one end of a thread of length $$0.1m$$ whirled in a vertical circle. When the stone is at the lowest point of circle, tension in thread is $$52N$$, then velocity of the stone will be:

A stone of mass $$1kg$$ is tied to the end of a string of $$1m$$ length. It is whirled in a vertical circle. If the velocity of the stone at the top be $$4m/s$$. What is the tension in the string (at that instant)?

A stone at one end of a light string is whirled around a vertical circle. If the difference between the maximum and minimum tension experience by the string were $$2\ Kg$$, the mass of the stone must be: