Laws of Motion ...

A particle is moving in a vertical circle. The tension in the string when passing through two positions at angles $${30}^{o}$$ and $${60}^{o}$$ from vertical (lowest position) are $${T}_{1}$$ and $${T}_{2}$$ respectively, then

For the body moving in vertical circular motion, work done by centripetal and centrifugal forces will be:

Two cubes of size 1.0 m sides, one of relative density 0.60 and another of relative density=1.5 are connected by weightless wire and placed in a large tank of water.Under equilibrium the lighter cube will project above the water surface to a height of:

A glass marble whose mass is 20 gms falls from a height of 0.25 m and rebounds to a height of 1.6 m. If $$g = 9.8 m/s^2$$, find the impulse acting on the fall (in N - s)

A particle of mass $$m$$ is moving a uniform velocity $${v}_{1}$$. It is given an impulse such that its velocity becomes $${v}_{2}$$. The impulse is equal to

A particle of mass m is made to move with uniform speed $${ v }_{ 0 }$$ along the perimeter of regular hexagon. The magnitude of impulse at each corner of the hexagon is :

The speed of a motor increases from 1200 rpm to 1800 rpm in 20 s. How many revolutions does it make during these second?

An object is subjected to a force in the north-east direction. To balance this force, a second force should be applied in the direction.

The tension in the string revolving in a vertical circle with a mass m at the end which is at the lowest position  

When a simple pendulum is rotated in a vertical plane with constant angular velocity, centripetal force is: