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Work Energy and Power Test - 8

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  • Question 1
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    A person trying to lose weight (dieter) lifts a 10 kg mass, one thousand times, to a height of 0.5 m each time. Assume that the potential energy lost each time she lowers the mass is dissipated. How much work does she do against the gravitational force?

    Solution

    Work done by force applied against gravity for one lift will be

    W = Fs = mgh = 10 × 9.8 × 0.5 = 49J

    So work done for 1000 lifts = 49 x 1000 = 49000 J

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