Gravitation Tes...

What is the percentage decrease in the weight of  a body when it is taken 32 km below the surface of the earth? [Radius of the earth=6400km]

The value of $$'g'$$ at a depth of $$80 km$$ will be (Radius of earth $$= 6400 km$$ and value of $$'g'$$ on the surface of earth is $$10m/s^2$$)

The value of gravitational constant depends upon : 

A body has weight (W) on the ground. The work which must be done to lift it to a height equal to the radius of the earth, R, is

The ratio of the radius of a planet A to that of planet B is $$r$$. The ratio of accelerations due to gravity for the two planets is $$x$$. The ratio of the escape velocities from the two planets is :

Consider Earth to be a homogeneous sphere. Scientist A goes deep down in a mine and scientist B goes high up in a balloon. The gravitational field measured by

The ratio of acceleration due to gravity at a depth $$h$$ below the surface of earth and at a height $$h$$ above the surface for $$h<<R$$

If $$R$$ is radius of the earth and $$W$$ is work done in lifting a body from the ground to an altitude $$R$$, the work which should be done in lifting it further to twice that altitude is:

A space craft is launched in a circular orbit very close to the earth. What additional velocity should be given to the space craft so that it might escape the earth's gravitational pull:

A particle hanging from a spring stretches it by $$1 cm$$ at earth's surface. Radius of earth is $$6400 km$$. At a place $$800 km$$ above the earths surface, the same particle will stretch the spring by