Gravitation Tes...

A body weighs $$72\ N$$ on the surface of earth. What is the gravitational force on it due to earth at a height equal to half the radius of the earth from the surface?

At what depth from the surface of the earth (in terms of the radius of earth) the acceleration due to gravity will be: $$\dfrac {2g}{5}$$?

The value of g on the earth's surface is $$980\ cm\ s^{-2}$$. Its value at a height of $$64\ km$$ from the earth's surface is

At a place, the value of 'g' is less by $$1$$% than its value on the surface of the Earth (Radius of Earth, $$R = 6400\ km$$). The place is:

A spring balance is graduated when it is at sea level. If a body is weighed at consecutively increasing heights from earth's surface, the weight indicated by the balance:

At what height from the surface of the earth (in terms of the radius of earth) the acceleration due to gravity will be $$\dfrac {g}{100}?$$

At a point very near to the earth's surface, the acceleration due to gravity is g. What will be the acceleration due to gravity at the same point if the earth suddenly shrinks to half its radius without any change in its mass?

As the altitude increases, the acceleration due to gravity:

If earth's radius were to hypothetically shrink by $$1\%$$, the value of $$G$$ would:

The value of universal gravitational constant $$G$$ is-